- #1

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## Homework Statement

I'm studying function simplification in boolean algebra, and I didnt understand the following step:

(

**NOT**A)(

**NOT**B)(C) + B = (

**NOT**A)(C) + B

What happened to the NOT B?

- Thread starter rehcarlos
- Start date

- #1

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I'm studying function simplification in boolean algebra, and I didnt understand the following step:

(

What happened to the NOT B?

- #2

- 15,393

- 685

Expand (¬A)(C) on the right hand side as (¬A)(¬B)(C)+(¬A)(B)(C) and simplify.

- #3

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but I still don't get it, I mean...

I need to know whats the next step of (NOT A)(NOT B)(C) + B. In your answer, you are saying that I need to expand the right side... but in a real exercise, I wouldn't know what the right side would look like

- #4

- 15,393

- 685

Expand B as B = (any boolean expression whatsoever)B + B. Here we'll use B = (¬A)(C)(B) + B. Then the left hand side becomes (¬A)(¬B)(C) + (¬A)(C)(B) + B. Combine the first two terms and simplify to yield (¬A)(C).

- #5

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Got it! Thanks

- #6

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test

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