Affine Varieties - the x-axis in R^2

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The discussion focuses on the isomorphism between the coordinate ring of the x-axis in \(\mathbb{R}^2\), specifically \(\mathbb{R}[x,y]/(y)\), and \(\mathbb{R}[x]\). This is established through the application of the First Isomorphism Theorem for rings, with the mapping defined as \(\Phi: \mathbb{R}[x,y] \rightarrow \mathbb{R}[x]\) where \(\Phi\left(\sum \alpha_{ij}x^i y^j\right) = \sum \alpha_{i0}x^i\). The x-axis is confirmed to be irreducible due to the resulting integral domain from this isomorphism.

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In Dummit and Foote, Chapter 15, Section 15.2 Radicals and Affine Varieties, Example 2, page 681 begins as follows:

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"The x-axis in \mathbb{R}^2 is irreducible since it has coordinate ring

\mathbb{R}[x,y]/(y) \cong \mathbb{R}[x]

which is an integral domain."

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Can someone please help me to show formally and rigorously how the isomorphism

\mathbb{R}[x,y]/(y) \cong \mathbb{R}[x] is established.


I suspect it comes from applying the First (or Fundamental) Isomorphism Theorem for rings ... but I am unsure of the mappings involved and how they are established

Would appreciate some help>

Peter
 
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Consider ##\Phi: R[X,Y]\rightarrow R[X]: \sum \alpha_{ij}X^i Y^j \rightarrow \sum \alpha_{i0}X^i##. So we evaluate the polynomial in ##0##. These evaluation maps usually work in these contexts.
 
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