After how many time constants is capacitor energy 1/4?

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SUMMARY

The discussion focuses on determining the time required for the stored energy of a discharged capacitor to reach one-fourth of its initial value. The correct solution utilizes the equation U = Q²/2C, leading to the conclusion that t = 0.693RC after one time constant. An initial attempt using the equation U = Qmaxε/2 resulted in confusion due to the incorrect assumption that Qmax equals Qi throughout the discharge process. The key takeaway is that the energy equations must be applied correctly to reflect the changing charge in a discharging capacitor.

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  • Understanding of capacitor discharge principles
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  • Knowledge of time constant calculations in RC circuits
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  • Learn about energy storage in capacitors and the implications of charge changes
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David Day
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Homework Statement


[/B]
After how many time constants
is the stored energy of a discharged capacitor one-fourth its initial value?

Homework Equations


[/B]
(1) U = Q2/2C

(2) U = Qmaxε/2

(3) q(t) = Qie-t/RC

The Attempt at a Solution



The solution can be correctly attained using the first equation:

(1/4) Q2/2C = (Qie-t/RC)2/2C

(1/4) = e-2t/RC

t = 0.693RC

However, I first attempted to use equation (2) but could not get the correct answer. I can't figure out what mistake or incorrect assumption I'm making. My attempt follows:

(1/4) Qmaxε/2 = Qmaxe-t/RCε/2

(1/4) = e-t/RC

As can be seen here, this answer is off from the first by an exponent of two. Q2/2C and Qmaxε/2 are mathematically equivalent, so I'm not sure where I'm making the error. Is it not correct to assume Qmax = Qi?

I'd really appreciate some help in clearing this up!

EDIT: I may see my problem. The ε in equation (2) is proportional to Q and will thus be changing, i.e, it's not equal to the ε on the other side of the equation except when t = 0, so I need to change it to Q/C, which will be the same form as equation (1). I'm not sure if this is the problem or not...
 
Last edited:
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David Day said:
After how many time constants
is the stored energy of a discharged capacitor
Do you mean a "discharging" capacitor?
David Day said:
(1/4) Qmaxε/2 = Qmaxe-t/RCε/2
If the capacitor is discharging, can you use the same ε on the RHS of this equation as in the LHS?

Edit: I see you found the error in your equation by yourself while I was typing my response. Well done!
 
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