Energy dissipated in the resistors in a 2 mesh RC circuit

• Eduardo Leon
In summary: Although I have no idea of how to proceed, I did calculate the currents and voltages for each part of the circuit. Below are the results:For the switch:I find the current passing by the amperemeter (IA) and the voltage across the voltmeter VV after a long time t (t>5 time constants). The current is I find the voltage across the voltmeter VV passed 10 milliseconds. The voltage is For the resistor:The energy dissipated in the resistor until an instant t is The energy dissipated in the resistor until an instant t is The energy dissipated in the resistor until an instant t is For
Eduardo Leon

Homework Statement

Hi mates, I have problems solving the third part of this exercise, I've already done all the previous calculations.

Given the following circuit, where the switch S is open, the power supply = 50 volts and:
• The initial charge in the C capacitor: QC = 0 coulombs
• The initial charge in the 2C capacitor: Q2C = 20^-6 coulombs
Calculate (with real instruments):
1. Switch⇒I find the current passing by the amperemeter (IA) and the voltage across the voltmeter VV After a long time t (t>5 time constants). (Done).
2. Switch⇒II find the voltage across the voltmeter VV passed 10 milliseconds. (Done).
3. Switch⇒III next get the final reading of the voltmeter VV at a given time t (t >0 ∧ t< 5 time constants) and the energy dissipated in the resistors till that instant.

Homework Equations

• Ohm's law: R=ΔV/i
• Capacitance: C=q/ΔV
• Kirchoff's laws: Σi=0 ∧ ΣΔV=0
• Energy gived by the battery until an instant t
• Energy dissipated in the resistor until an instant t
• Energy stored in the capacitor until an instant t

The Attempt at a Solution

As stated before, I've done the first and the second parts.

For the first:
• Amps*
• Volts*
For the second:
• Volts*
For the third:
Well, here is where i get lost, because I dont't know how to study and analize the circuit formed at this point, I've only seen discharging RC circuits whis a single current, one resistor and one capacitor due those elements could be joined into their equivalent ones, but here, I get 2 resistors, 2 capacitors and 2 meshes, like this one.

I know that the initial charges at this point are:

In order to get the initial charge in the C capacitor I used the voltage obtained in the voltmeter in the second part at the 10 milliseconds, because are connected parallel. So, multiplying that voltage times the capacitance, we get
The initial charge in the 2C capacitor stills equal, since its an ideal capacitor, so is the same: Q2C = 20^-6 coulombs

Attachments

• 33333333333333.png
19.6 KB · Views: 318
• attachment.jpg
30.4 KB · Views: 656
• Image1.gif
621 bytes · Views: 452
• Image2.gif
666 bytes · Views: 449
• Image3.gif
624 bytes · Views: 448
• 58_59e4a5e4c7a317067e0e748d4c7303e8.png
1.2 KB · Views: 408
• 55_39ed5ab39f3e1b932d58b8143acf9655.png
1 KB · Views: 419
• 49_549e15a8fc3c64f775b461c0ce4c83f2.png
870 bytes · Views: 416
• 73_a3a7a2e80e63986351b15fb412bb6203.png
981 bytes · Views: 448
• 34_76bab7f98db551c5bfbe82b73004a907.png
1.2 KB · Views: 463
• 49_f93ffa7bf895f1ac07d8dc5df756a1e0.png
1.3 KB · Views: 451
Last edited by a moderator:
It would help things if you first produced a clearer circuit diagram.

What is an RC circuit?

An RC circuit is an electrical circuit that contains both a resistor (R) and a capacitor (C). It is commonly used in electronic devices to control the flow of electricity and store energy.

What is energy dissipation?

Energy dissipation is the process by which energy is converted into heat and lost from a system. In the context of an RC circuit, it refers to the energy that is lost as heat in the resistors.

How is energy dissipated in a 2 mesh RC circuit?

In a 2 mesh RC circuit, energy is dissipated in the resistors due to the flow of current through them. As the current passes through the resistors, it encounters resistance, which causes the electrical energy to be converted into heat energy.

What factors affect the amount of energy dissipated in an RC circuit?

The amount of energy dissipated in an RC circuit is affected by the resistance of the resistors, the capacitance of the capacitor, and the voltage applied to the circuit. The higher the resistance and voltage, and the lower the capacitance, the more energy will be dissipated in the resistors.

How can energy dissipation be minimized in an RC circuit?

To minimize energy dissipation in an RC circuit, the resistance of the resistors can be reduced, the capacitance of the capacitor can be increased, and the voltage applied to the circuit can be lowered. Additionally, using more efficient resistors and capacitors can also help reduce energy dissipation.

• Introductory Physics Homework Help
Replies
9
Views
476
• Introductory Physics Homework Help
Replies
3
Views
1K
• Introductory Physics Homework Help
Replies
6
Views
2K
• Introductory Physics Homework Help
Replies
9
Views
2K
• Introductory Physics Homework Help
Replies
5
Views
6K
• Introductory Physics Homework Help
Replies
62
Views
3K
• Introductory Physics Homework Help
Replies
4
Views
341
• Introductory Physics Homework Help
Replies
3
Views
156
• Introductory Physics Homework Help
Replies
4
Views
2K
• Introductory Physics Homework Help
Replies
10
Views
5K