1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Air ballon and ball question. HELP

  1. Sep 9, 2010 #1
    Air ballon and ball question. HELP!!!

    1. The problem statement, all variables and given/known data
    A balloon is going straight up at 21.5 m/s. You are in the ballon and you throw a ball at 13.2 m/s straight up while riding in the balloon. If the ball hits the ground at 34.5s

    a) How long oes it take the ball to stop once it leaves your hand at the ball's highest point?

    b) How high did the ball go after leaving your hand? (from your hand to the highest point)

    c) How high off the ground did the ball go?

    d) How fast was the ball traveling when it hit the ground? (Not zero)

    e) How high off the ground was the ball when it was released

    2. Relevant equations
    x=1/2 (Vi+Vf)t
    a= (Vf-Vi)/t
    Vf=Vi + at
    Vf^2= Vi^2 + 2ax
    X= Vi t + 1/2(at)^2


    3. The attempt at a solution
    a) Vi= 13.2 m/s g=9.81 Vf= 0m/s t=???
    t= (Vf-Vi)/a
    t= (13.2-0)/9.81
    t= 1.35 Seconds

    b) x= 1/2 (Vi+Vf) t
    x= 1/2 (13.2) 1.35
    x= 8.88 m

    c) Not sure yet

    d) A guess
    Vf= -9.81 (34.5) + 0
    Vf= -338.445 m/s

    e) no idea

    Any help/corrections are appreciated to better my understanding. Thank you
  2. jcsd
  3. Sep 9, 2010 #2
    Re: Air ballon and ball question. HELP!!!

    You need to use the principle of relative motion to get the correct initial velocity. The velocity of the ball relative to the balloon is 13.2 m/s, but the balloon is also has a velocity...
  4. Sep 9, 2010 #3
    Re: Air ballon and ball question. HELP!!!

    Is there an equation for that? Are my initial answers wrong as far as the equations used i just have the values wrong?
  5. Sep 9, 2010 #4
    Re: Air ballon and ball question. HELP!!!

    Yes, the velocity's are simply added together to get the velocity of the ball relative to the ground or reference frame. From that point all the steps should be the same. Set your velocity final to 0m/s to find the time it takes to reach a peak. Use that time to calculate the height it reached. The only thing is there is some initial height when the ball is released (question E) and you only calculated the height it goes up from that release point. So you need to use the total time given to back calculate that initial height. Then use that total height (or just the initial height plus the initial velocity) to calculate the speed it would reach before hitting the ground (question C). So it seems as the questions are out of order, but thats how I'd do it.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook