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How many particles of air do their lungs contain after inhaling?

  1. Apr 10, 2013 #1
    A submarine has run into trouble and is stuck at the bottom of the ocean. Several people are on board and must make their way to the surface without any diving gear. The air pressure aboard the submarine is 3.400 atm. The air temperature inside the submarine is 16.36 °C and you can take body temperature (inside the lungs) to be 37.64 °C.
    The first person to leave also takes a breath as deep as possible by exhaling as far as possible (leaving a volume of 1.170 L in their lungs), and then slowly inhaling to increase their lung volume by 4.580 L. His body temperature is also 37.64 °C.

    (i)How many particles of air do their lungs contain after inhaling?
     
  2. jcsd
  3. Apr 10, 2013 #2
    You need to demonstrate an attempt at solving this in order to get help here.
     
  4. Apr 10, 2013 #3
    I used V1/T1=V2/T2
    where V1=4.88, T1=309.19k, T2=286.7k and V2 is the unknown.
    then I put V2 in the formula PV2=nRT P-3.5atm T-309.19
    I got 6.16^e-3 but the answer is 4.92e+23
    ... far out
     
  5. Apr 10, 2013 #4
    Why is V2 is unknown? You are given the volume after the exhalation, and you are told by how much it increases after the inhalation.
     
  6. Apr 10, 2013 #5
    awwwww
    I just used PV=nRT
    P- atm= 202.658 V=5.13 T=309.19
    but its still not right.... where went wrong??
     
  7. Apr 10, 2013 #6
    Why is V = 5.13? And this is 5.13 of what? What units should you be using?
     
  8. Apr 10, 2013 #7
    the volume of lung? 1.7+4.58m3
    then times 6.02*10e23...?
     
  9. Apr 10, 2013 #8
    Can you image what a cubic meter looks like? Now imagine someone's lungs which are MULTIPLE cubic meters.
     
  10. Apr 10, 2013 #9
    oh! stupid me!
    so that will be 0.00513m3
    ummmm in getting 2.44*10^23 ..
     
  11. Apr 10, 2013 #10
    Are you unable to sum 1.17 and 4.58?
     
  12. Apr 10, 2013 #11
    oh.. that was a typo.. should be 'increase their lung volume by 4.880 L' and so 0.00593 for V
     
  13. Apr 10, 2013 #12
    So, do you get the right answer now?
     
  14. Apr 10, 2013 #13
    no.... im getting 2.81*10^20
    .... couldn't figure out where has gone wrong...
     
  15. Apr 10, 2013 #14
    What value for P are you using?
     
  16. Apr 10, 2013 #15
    oh right! I've got the answer now ;)
    Thank you sooo much
     
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