An audience of 2750 fills a concert hall of volume 35000 m3. If there were no ventilation, by how much would the temperature of the air rise over a period of 2.0 h due to the metabolism of the people (70 W/person)?
Cv= (3/2) R
The Attempt at a Solution
Since the v keeps constant, we use Cv to calculate the change of T of the air. We want to get the value of ΔT and we know n and Cv.
The total heat release by audience: 2750 x 70 x 2.0 x 60 x 60 = 1386000000 J
PV=nRT, so n = PV/RT = (1.013 x 10^5 x 35000) / (8.314 x (20 + 273.15)) = 1454713 mole
Cv = 1.5 x 8.314 =12.471
ΔT = Q/ (n x Cv) = 76.3 K... which doesn't make sense.