1. The problem statement, all variables and given/known data The air temperature and pressure in a laboratory are 22°C and 1.3 atm. A 2.05 L container is open to the air. The container is then sealed and placed in a bath of boiling water. After reaching thermal equilibrium, the container is open. How many moles of air escape? 2. Relevant equations ni=PiVi/RTi nf=PfVf/RTf 3. The attempt at a solution I easily found ni by plugging in for the top equation (131690 Pa*.00205 m^3) / (8.31 * 295K) and got .110 mols then I found the nf by doing the same thing except assuming that Pf is 1 atm (101300 Pa) and that the Tf is 100 deg C(273 K), with constant volume. I got .066 Then I subtracted the ni-nf to get how many mols are left. Why wouldn't this work?