Thermodynamics: two pistons; different pressures, volumes, and temperatures

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Homework Help Overview

The discussion revolves around a thermodynamics problem involving two thermally insulated vessels containing oxygen at different pressures, volumes, and temperatures. The vessels are connected by a narrow tube with a valve that is initially closed, and the problem seeks to determine the final temperature and pressure once the valve is opened and the gases mix.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses uncertainty about which equations are relevant and how to approach the problem. They mention a potential method of treating the tube as another vessel but are unsure how to proceed.
  • One participant suggests using the conservation of internal energy and provides a formula for final pressure based on initial conditions. They also mention calculating initial moles of oxygen using the ideal gas law.
  • Another participant discusses the degrees of freedom of diatomic oxygen and relates it to internal energy, referencing the equipartition of energy theorem.

Discussion Status

The discussion includes attempts to clarify the relationships between pressure, volume, and temperature in the context of an isolated system. Some participants provide guidance on relevant equations and concepts, while others express their understanding and seek further clarification on specific points.

Contextual Notes

Participants note that the system is isolated, which affects the internal energy considerations. There is also mention of limited coverage of the topic in class, which may contribute to the original poster's confusion.

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Homework Statement

20-p-013-alt.gif
Two thermally insulated vessels are connected by a narrow tube fitted with a valve that is initially closed as shown in the figure. One vessel of volume V1 = 15.2 L, contains oxygen at a temperature of T1 = 280 K and a pressure of P1 = 1.77 atm. The other vessel of volume V2 = 23.0 L contains oxygen at a temperature of T2 = 460 K and a pressure of P2 = 2.35 atm. When the valve is opened, the gases in the two vessels mix and the temperature and pressure become uniform throughout.

What is the final temperature?

What is the final pressure?

Homework Equations


I really do not know which are relevantPiVi/ Ti = PfVf/Tf

1 atm = 101325 pa

1L = 1000cm3ΔE internal = Q (isovolumetric process)

ΔE internal = W (adiabatic process)

ΔE internal = Q + W (first law of thermodynamics)

The Attempt at a Solution


I really do not know where to start or what formula to use so any hints would be helpful. We didn't have very much time to cover all this at all (very watered down) so if there is something I am supposed to give and don't give, then sorry.

The way I see it, I think you would solve for the tube as if it were another vessel / piston, but I am not sure how to even do that :(

P1 = 179345 pa
V1 = 152 m3
T1 = 280 kelvins

P2 = 238113 pa
V2 = 230 m3
T2 = 460 kelvins
 
Last edited:
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as the system is isolated ,its internal energy will remain constant.
oxygen is diatomic, so internal energy of of n moles =2.5nRT=2.5PV
Ei=Ef
Ei=2.5P1V1+2.5P2V2
let final pressure be P,then
Ef=2.5P(v1+V2)
so,P=(P1V1+P2V2)/(V1+V2)

initial moles of oxygen=(P1V1)/RT1 +(P2V2)/RT2
so,P*(V1+V2)=(initial moles)*R*T (T is final temp.)
solve to get,T.
 
Thank you so much. I got them both now even though you practically did the formula for me.

I knew that it was an isolated system too but didn't see how that would help either but...

pcm said:
oxygen is diatomic, so internal energy of of n moles =2.5nRT=2.5PV
Don't know where you got this from. And for temperature, I didn't realize you could use the ideal gas law like that (adding the pressure / volumes of the cylinders equal to find n).Thanks.
 
oxygen is diatomic ,so it has 3 translational and 2 rotational degrees of freedom.
so,internal energy per mole of oxygen is (3+2)/2 *RT ...(equipartition of energy theorem)
 

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