Two thermally insulated vessels are connected by a narrow tube fitted with a valve that is initially closed as shown in the figure. One vessel of volume V1 = 15.2 L, contains oxygen at a temperature of T1 = 280 K and a pressure of P1 = 1.77 atm. The other vessel of volume V2 = 23.0 L contains oxygen at a temperature of T2 = 460 K and a pressure of P2 = 2.35 atm. When the valve is opened, the gases in the two vessels mix and the temperature and pressure become uniform throughout.
What is the final temperature?
What is the final pressure?
I really do not know which are relevant
PiVi/ Ti = PfVf/Tf
1 atm = 101325 pa
1L = 1000cm3
ΔE internal = Q (isovolumetric process)
ΔE internal = W (adiabatic process)
ΔE internal = Q + W (first law of thermodynamics)
The Attempt at a Solution
I really do not know where to start or what formula to use so any hints would be helpful. We didn't have very much time to cover all this at all (very watered down) so if there is something I am supposed to give and don't give, then sorry.
The way I see it, I think you would solve for the tube as if it were another vessel / piston, but I am not sure how to even do that :(
P1 = 179345 pa
V1 = 152 m3
T1 = 280 kelvins
P2 = 238113 pa
V2 = 230 m3
T2 = 460 kelvins