Air Puck Correct Method or not

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SUMMARY

The discussion centers on the physics problem involving an air puck of mass 0.25 kg revolving in a circle of radius 1.0 m, with a 1 kg mass suspended vertically. The tension in the string is calculated to be 9.8 N, which is also the horizontal force acting on the string. The speed of the puck is determined to be 6.3 m/s using the centripetal force equation. While the calculations for tension and speed are correct, the reasoning for the horizontal force requires clarification regarding the angle of the system.

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Air Puck ! Correct Method or not...

Homework Statement



An air puck of mass 0.25kg is tied to a string and allowed to revolve in a circle of radius 1.0m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table and a mass of 1kg is tied to it. The suspended mass remains in equilibrium while the puck on the tabletop revolves

a. What is the tension in the string ?
b. What is the horizontal force acting on the string ?
c. What is the speed of the puck ?

Homework Equations



\SigmaF = m * a
F_c = (m * v^2) / r
a_c = v^2 / r

The Attempt at a Solution



a.
\SigmaF_y = m * a = 0
T - mg = 0
T = mg = 1.0kg * 9.8m/s^2 = 9.8N

b.
F_c = Tension on th string = 9.8N

c.
F_c = (m * v^2) / r = 9.8N
(0.25kg * v^2) / 1.0m = 9.8N
v = \sqrt{39.2} = 6.3 m/s

Is this correct...THANKS!
 
Last edited:
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You seem to have it under control.
 
3a. is correct, but it has incorrect --as near as I can tell- reasoning. Just recall Newton's Third Law for centripetal forces. Also, for 3b. it asks what is the horizontal force is; which requires an angle for the center of the system; not certain on how you are supposed to acquire that answer.
 
Last edited:
andrevdh said:
You seem to have it under control.

Thanks a lot !
 
very very helpful
 
Last edited:

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