1. The problem statement, all variables and given/known data A fire helicopter carries a 625 kg empty water bucket at the end of a cable 21.7 m long. As the aircraft flies back from a fire at a constant speed of 36.6 m/s, the cable makes an angle of 35.3° with respect to the vertical. Calculate the force of air resistance on the bucket. 2. Relevant equations F=ma. Fnet=0 3. The attempt at a solution I started with the rationalization that constant speed implies 0 acceleration, meaning Fnet=0 in both the x and y direction. Dividing the forces up into Fnety=T(tension in the cable)-W(mg) and Fnetx is where I get stuck. If the acceleration is 0, then which force is opposing air resistance? Should I be calculating the horizontal component of the displacement from the vertical? Help, please!