Air Resistance Problem: Dropping two balls with different masses

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The discussion centers on solving an air resistance problem involving two balls of different masses dropped simultaneously. Participants emphasize the importance of using free body diagrams to illustrate the forces acting on each ball, including gravitational force and air resistance. The conversation highlights that, despite differing masses, both balls will experience the same acceleration due to gravity in a vacuum, but air resistance will affect them differently in real conditions. A good faith attempt at a solution should include calculations or qualitative analysis of how air resistance impacts the motion of each ball. Understanding these principles is crucial for accurately addressing the problem.
Richard8786
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Homework Statement
A certain ping-pong ball has mass of 2.4 g and a terminal speed of 10.0 m/s as it falls through air. Suppose the same type of ping-pong ball is then filled with water such that it has a new mass of 21.6 g and it is dropped through the air. (a) Determine the acceleration of the water-filled ball as it falls at 10.0 m/s through the air. (b) Determine the terminal speed of the water-filled ball assuming that the air resistance is proportional to the square of the speed.
Relevant Equations
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I am not sure how to even start this problem.
 
Last edited:
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You are supposed to show some "good faith" attempt at a solution. See guidelines.
 
Richard8786 said:
I am not sure how to even start this problem.
Usual place: free body diagrams showing the forces acting in the different cases.
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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