Air Resistance Problem: Dropping two balls with different masses

Richard8786
Messages
1
Reaction score
0
New user has been reminded to show their work on schoolwork problems
Homework Statement
A certain ping-pong ball has mass of 2.4 g and a terminal speed of 10.0 m/s as it falls through air. Suppose the same type of ping-pong ball is then filled with water such that it has a new mass of 21.6 g and it is dropped through the air. (a) Determine the acceleration of the water-filled ball as it falls at 10.0 m/s through the air. (b) Determine the terminal speed of the water-filled ball assuming that the air resistance is proportional to the square of the speed.
Relevant Equations
None
I am not sure how to even start this problem.
 
Last edited:
Physics news on Phys.org
You are supposed to show some "good faith" attempt at a solution. See guidelines.
 
Richard8786 said:
I am not sure how to even start this problem.
Usual place: free body diagrams showing the forces acting in the different cases.
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
TL;DR Summary: Find Electric field due to charges between 2 parallel infinite planes using Gauss law at any point Here's the diagram. We have a uniform p (rho) density of charges between 2 infinite planes in the cartesian coordinates system. I used a cube of thickness a that spans from z=-a/2 to z=a/2 as a Gaussian surface, each side of the cube has area A. I know that the field depends only on z since there is translational invariance in x and y directions because the planes are...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top