Airplane Braking Distance Question

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SUMMARY

The discussion addresses the calculation of braking distances for an airplane when decelerating from two different speeds: 56 mi/h and 28 mi/h. It concludes that the distance traveled when braking from 56 mi/h is four times greater than that from 28 mi/h, based on the equations of motion. The key equations utilized include v = v0 + at and x = x0 + 2a(x - x0), confirming that the time to stop is directly proportional to the initial speed, leading to the conclusion of four times the distance.

PREREQUISITES
  • Understanding of basic physics concepts, specifically kinematics.
  • Familiarity with the equations of motion, particularly v = v0 + at and x = x0 + 2a(x - x0).
  • Knowledge of units of speed, specifically miles per hour (mi/h) and their conversion to meters per second (m/s).
  • Ability to perform algebraic manipulations and solve equations.
NEXT STEPS
  • Study the principles of kinematics in physics to deepen understanding of motion equations.
  • Learn about the effects of acceleration on stopping distances in various vehicles.
  • Explore real-world applications of braking distance calculations in aviation safety.
  • Investigate how different factors, such as weight and surface conditions, affect braking distances.
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as aviation professionals and engineers interested in aircraft performance and safety metrics.

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Homework Statement


Assuming equal rates of acceleration in both cases how much further would you travel if braking from 56mi/h to rest than from 28mi/h ?
a, 5.2 times farther
b, 4.8 times farther
c, 3.2 times farther
d, 4.0 times farther

Homework Equations



not really sure what i should use.
v=v0+at
x= x0+2a(x-x0)

The Attempt at a Solution


0-56/0-28=56/28=2
 
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V1 (56 m/s) is twice as great as V2 (28 m/s) so the time needed to stop is going to be doubled, due to a the equal acceleration. So you take the difference in the velocity values (twice as great), and in the time values (twice as great), and you come up with the four times farther by multiplying the aforementioned values.
 
ohh. thank you!
 

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