Why Does an Airplane Pilot Experience Limits on Radial Acceleration?

[kimikims]

I tried workin this problem out.. and it's not working!

---
An airplane is flying in a horizontal circle at a
speed of 48.1 m/s. The 94.1 kg pilot does not
want his radial acceleration to exceed 7:.39 g.
The acceleration of gravity is 9.8 m/s^2

1) What is the minimum radius of the circular
path? Answer in units of m.

7.39g (9.8m/s^2) = 72.422 m/s^2
do I need to square root 72.422??


2) At this radius, what is the net centripetal force
exerted on the pilot by the seat belts,
the friction between him and the seat, and so
forth? Answer in units of N.

N = mg + m (V^2/m)

is this the right formula?? what would m and v be??

 

[kimikims]

Is this right??

Speed = 48.1 m/s
g = 9.8 m/s^2

Problem #1

7.39 g (9.8 m/s^2) = A
A = 72.422

R = V^2 / A
R = (48.1 m/s)^2 / 72.422
R = 31.94

Problem #2

F = mV^2 / R
What's m??
F = (?)m x (4.8)^2 / 31.94

 

[thermodynamicaldude]

Remember that A(centripetal) = v^2 / R...

...so your answer to problem 1 looks correct.

On problem 2, how did you go from a velocity of 48.1 m/s to that of 4.8 m/s? The mass would just be the pilots mass...because its asking for the centripetal force acting on the pilot.

 

[kimikims]

Remember that A(centripetal) = v^2 / R...

...so your answer to problem 1 looks correct.

On problem 2, how did you go from a velocity of 48.1 m/s to that of 4.8 m/s? The mass would just be the pilots mass...because its asking for the centripetal force acting on the pilot.

Sorry I meant 48.1 m/s not 4.8 m/s...

So it would be:

Fc = m (V^2/R)
Fc = 94.1 [(48.1)^2 m/s / 31.9)

Fc = 6824.78 N?

 

[thermodynamicaldude]

Looks good. :-D

 

[kimikims]

Looks good. :-D

Thank you!