Airplane diving with a circle radius

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Homework Help Overview

The discussion revolves around a physics problem involving an airplane pilot pulling out of a dive while following a circular path. The problem specifies the pilot's mass, the radius of the circular path, and the speed at the bottom of the circle, prompting participants to determine the magnitude of the pilot's acceleration.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relevance of centripetal acceleration and question the initial assumptions about the forces acting on the pilot. Some express confusion about the relationship between centripetal acceleration and gravitational acceleration.

Discussion Status

There is an ongoing exploration of the concepts of centripetal acceleration and the effects of gravity on the pilot's overall acceleration. Some participants suggest that the problem may require considering both types of acceleration, while others clarify that the magnitude of acceleration can be determined using specific formulas.

Contextual Notes

Participants are navigating through the implications of the problem's wording, particularly regarding the request for the magnitude of acceleration without direction. There is also mention of the pilot's experience of acceleration in different flight conditions.

Robertoalva
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1. A 55 kg airplane pilot pulls out of a dive by following, at constant speed, the arc of a circle whose radius is 320 m. At the bottom of the circle, where her speed is 230 km/h, what is the magnitude of her acceleration?



Homework Equations



v^2= vi^2 +2a(x-xi)

The Attempt at a Solution



i suppose that the plane has a height of the radius and the initial velocity would be 0. Am I wrong? if I am, please tell me!
 
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i think only acceleration will be of gravity.
 
The equation you cite isn't relevant. Hint: centripetal acceleration.
 
nil1996 said:
i think only acceleration will be of gravity.

No. It's moving in a circle.
 
CWatters said:
No. It's moving in a circle.
I first saw at the eqn he has given and so declared as the acceleration is of gravity.
I think you are right it is centripetal acceleration.
 
oh! that's true! i totally forgot about centripetal forces!
 
You are visualizing the question wrongly I believe. The aeroplane is in the air, and is heading down towards the Earth. The pilot then pulls out of the dive - he will not go vertically up straight away, rather, he will move along a curved arc upwards. You have the radius of this arc, you have the velocity, and you have the mass. This is a straightforward formula application question.
 
if centripetal force is Fc= m(v^2/r)
then
the centripetal acceleration formula can be derived from the circular acceleration right? a=v^2 /r ,right?
 
Yes. All you need to do is divide the force by the object's mass to get it's acceleration.
 
  • #10
really? so i just do:

Fc=m (v^2/r)
Fc/m=a ? i already got confused!

they are giving me:
m=55kg
r=320m
v=230km/h

and a=v^2/r, wouldn't it be easier to just substitute the values in this formula?
 
  • #11
You don't need the mass to calculate the acceleration. You may use the formula in the last line. All the same thing really.
 
  • #12
The answer is not just the centripetal acceleration :-)
 
  • #13
they want me to find the magnitude of her acceleration, which tells me that they only want a numerical value without a direction, so if they are not asking only for centripetal acceleration then what is it!?
 
  • #14
In level flight a pilot experiences 1g.
 
  • #15
CWatters said:
The answer is not just the centripetal acceleration :-)

Why do you say that?
 
  • #16
I take it back. She feels like she is accelerating at v^2/r + g but is actually only accelerating at v^2/r.
 
  • #17
so how this affects the acceleration? would it be a=(centripetal accel.)(gravity) ??
 
  • #18
Robertoalva said:
so how this affects the acceleration? would it be a=(centripetal accel.)(gravity) ??
No, you already have the answer in the last line of your post #10.
Acceleration is completely determinable by knowing the position as a function of time. With that information, the forces that led to that pattern of movement become irrelevant.
 

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