Airplane pilot in a dive, net force, minimum speed, and normal force.

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The discussion revolves around a physics problem involving a pilot in a circular dive, focusing on calculating net force, normal force, and minimum speed to prevent falling out. The pilot's weight and normal force are considered, with initial confusion about net force being zero due to the forces canceling each other out. Clarifications highlight that the pilot experiences acceleration due to the changing direction of motion, necessitating a net force directed towards the center of the circle. The calculations for the forces at the top and bottom of the circle reveal errors in sign and interpretation, prompting further analysis of the forces involved. The conversation emphasizes the importance of understanding the relationship between net force, acceleration, and the direction of forces in circular motion.
timnswede
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Homework Statement


A 65 kg airplane pilot pulls out of a dive by following at constant speed, the arc of a circle whose radius is 300 m. At the bottom of the circle her speed is 180 km/h.
a.) Calculate net force on pilot at bottom or circle.
b.) Calculate force exerted on pilot by seat at top and bottom of circle.
c.)Calculate minimum speed required so pilot doesn't fall out at top of circle if she's not wearing a seatbelt.

Homework Equations


Newton's second law, a=v^2/r

The Attempt at a Solution


For part a) the only two forces I could think of are the normal and weight down. So net force would be zero since they cancel each other out?

For part b) at top: n+mg=(v^2/r)m, plugging in numbers I get -95.3 N.
For the bottom n-mg=(v^2/r)m, and I got 1179 N.

For part c.) n would = 0, so mg=(v^2/r)m, and plugging in numbers I get 54.22 m/s^2.

I'm not sure if I did part a) right, but I feel pretty confident about the other parts, did I go about doing those parts correctly?
 
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timnswede said:
For part a) the only two forces I could think of are the normal and weight down. So net force would be zero since they cancel each other out?
If the net force is zero then there's no acceleration. Does an object moving in an arc at constant speed accelerate?
 
Oh, I should've thought of that, it does have acceleration since the direction is constantly changing. Would it be the answer I got for part b) then, 1179 N minus mg, 637? So 1179-637=542 N?
 
timnswede said:
Oh, I should've thought of that, it does have acceleration since the direction is constantly changing. Would it be the answer I got for part b) then, 1179 N minus mg, 637? So 1179-637=542 N?
No, a and b are not the same.
For a, what is the relationship between net force and acceleration?
For b, you have some signs wrong. Draw the FBD at top of circle. What forces apply in what directions? What must the net force be to move in a circle?
 
Well for part b I took the positive y-axis to be down at the top, I should've mentioned that, otherwise I'm not sure what would be wrong.
Net force and acceleration are towards the center of the circle in part a I think
 
timnswede said:
Well for part b I took the positive y-axis to be down at the top.
OK, but then be careful how you interpret the answer. For part b, top of circle you got a negative value. So is the seat pushing up on the pilot or down?
For part b, bottom of circle, even taking positive as down your answer is still wrong. Think that through again. E.g. which way is the centripetal force now?
Net force and acceleration are towards the center of the circle in part a I think
That's not what I asked. If the net force on a mass m is F and the resultant acceleration is a, what equation do you have? Apply that.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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