Alculate the x-component of the electric field

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Homework Help Overview

The problem involves calculating the x-component and y-component of the electric field produced by a uniformly distributed positive charge along the y-axis, with a negative point charge located on the positive x-axis. The context is within electrostatics, specifically focusing on electric fields generated by charge distributions.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the correctness of the derived expressions for the electric field components, particularly questioning the validity of the original poster's calculations and the use of notation such as "dEx".

Discussion Status

There is an ongoing examination of the expressions for the electric field components, with some participants suggesting that the original poster may have made a mistake in their calculations. Questions about the assumptions and the relevance of the negative charge are also being raised.

Contextual Notes

Participants note potential issues with the original poster's understanding of the problem setup and the need for clarity in their working process. There is also mention of a possible typo in the calculations and the implications of the negative charge on the electric field components.

ybad
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Homework Statement


Positive charge Q is distributed uniformly along the positive y-axis between y=0 and y=a . A negative point charge −q lies on the positive x-axis, a distance x from the origin

Calculate the x-component of the electric field produced by the charge distribution Q at points on the positive x-axis.

Calculate the y-component of the electric field produced by the charge distribution Q at points on the positive x-axis.

Homework Equations


E = q/4πε0r2
r2 = x2+y2

The Attempt at a Solution


So I was able to get the first part of the question relatively easily by using some techniques from the textbook, which resulted in the correct answer:

dEx = Q/4πε0x√(x2+a2)

But when I try to find the y-component, I get the answer:

dEy = (Q/(8πε0a))*(1-(x/(√x2+a2)))

This answer results in the following message from the website:
"Your answer either contains an incorrect numerical multiplier or is missing one."

I need help finding the problem since I don't know where I may have gone wrong.
 
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ybad said:
Calculate the x-component of the electric field produced by the charge distribution Q at points on the positive x-axis.

Calculate the y-component of the electric field produced by the charge distribution Q at points on the positive x-axis.
Just making sure; do you mean, "on the positive y-axis"?

ybad said:
dEx = Q/4πε0x√(x2+a2)
This gave you the correct answer? The units are incorrect. It might be simply a typo (because it's almost correct) but I want to make sure you understand how to do this before finding the y-component.

Edit:
The units are correct sorry... I misread the equation
 
Last edited:
Nathanael said:
This gave you the correct answer? The units are incorrect.
Assuming it is intended as Ex = Q/(4πε0x√(x2+a2)), the dimensions are correct (but yes, the expression is wrong... it should not tend to infinity as x tends to zero).
 
ybad said:
But when I try to find the y-component, I get the answer:
You don't say how you got that answer. We can't tell you where you went wrong if you don't post your working/logic.
 
ybad said:

Homework Statement


Positive charge Q is distributed uniformly along the positive y-axis between y=0 and y=a . A negative point charge −q lies on the positive x-axis, a distance x from the origin

Calculate the x-component of the electric field produced by the charge distribution Q at points on the positive x-axis.

Calculate the y-component of the electric field produced by the charge distribution Q at points on the positive x-axis.

Homework Equations


E = q/4πε0r2
r2 = x2+y2

The Attempt at a Solution


So I was able to get the first part of the question relatively easily by using some techniques from the textbook, which resulted in the correct answer:

dEx = Q/4πε0x√(x2+a2)

As pointed out in post #2, this answer is incorrect. Did you do a typo somewhere? And why "dEx"? It's just Ex.
You should be figuring the problem out for yourself rather than looking for formulas in a textbook.
If you did that you would have come up with one definite integral over y=0 to y=a for the x component, and a different definite integral, also over y=0 to y=a, for the y component.
BTW why is q mentioned in the problem?
Also, both the x and y components of the E field are obviously negative for all x. The answers have to be sign-reversed in x for x < 0.
 
rude man said:
BTW why is q mentioned in the problem?
Most likely for a later part of the question.
 

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