Algebra help what are the steps to get to the answer

  • Thread starter Thread starter Pepala
  • Start date Start date
  • Tags Tags
    Algebra
Click For Summary

Homework Help Overview

The discussion revolves around algebraic manipulations involving equations that relate variables x, π, θ, k, and Ω. The original poster seeks clarification on the steps taken to derive certain expressions and the reasoning behind them.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the algebraic transformations of the given equations, questioning specific steps and the relationships between variables. There is a focus on understanding how to manipulate the expressions involving z and the implications of dividing by z.

Discussion Status

Some participants have offered clarifications on specific steps, particularly regarding the computation of z and its implications. There is acknowledgment of potential typos and a request for further explanation on certain steps, indicating an ongoing exploration of the problem.

Contextual Notes

The original poster expresses confusion about the algebraic steps and seeks detailed explanations, highlighting the need for clarity in the manipulation of the equations. There is also a note about the consistency of variable notation, particularly regarding k and K.

Pepala
Messages
4
Reaction score
0
I am going through my notes and I don't understand the steps that are being taken to get to the solution, any help in figuring this out would be greatly appreciated!

It starts off with two equations

[tex]x=\frac{k+θπ}{1+θ^2/Ω}[/tex]

and

[tex]π= \frac{θ}{Ω}(\frac{k+θπ}{1+θ^2/Ω})[/tex]

then multiply x by Ω/Ω and we get

[tex]x=\frac{Ω(k+θπ)}{Ω+θ^2}[/tex]

let z represent [tex]\frac{Ω}{Ω+θ^2}[/tex]

then

[tex]x=z (k+θπ^2)[/tex]

then,

[tex]π= (θ/Ω)z(k+πθ)[/tex]

now here is where i get lost

K+ θπ > C

[tex]θπ=\frac{θ^2}{Ω}z[/tex]

how do we get to the next step? if we divide by z then we get (θπ)/z but π= (θ/Ω)(K+π) so θπ= (θ/Ω)(K+π)(1/z)... then what?

[tex]\frac{θ^2}{Ω}=\frac{1-z}{z}[/tex]

[tex]θπ=\frac{1-z}{z}[/tex]

z(K+θπ)=(1-z)(K+θπ)

θπ- (1-z)θπ=(1-z)K

[tex]zθπ= (1-z)k => θπ= \frac{1-z}{z} (K)[/tex]

= K/z

I am hoping that someone can explain in detail ( because I can't follow this) the steeps in between each step here.

Thank you for your time
 
Last edited:
Physics news on Phys.org
the first part of the question asks to minimize this

[tex]1/2 * (Ω(π^2)+x^2)+z(x+θπ-θπ^n-k)[/tex]
 
Do you need explanations for each step or just the step in red? I can explain the step in red for you, if you need more explained, let us know.

So we have [itex]\theta \pi = \displaystyle\frac{\theta^2}{\Omega}z[/itex] and we also have [itex]z = \displaystyle\frac{\Omega}{\Omega + \theta^2}[/itex]. I believe the step right after the red text is computed independent of the previous line. It is just using the fact that [itex]z = \displaystyle\frac{\Omega}{\Omega + \theta^2}[/itex] and is calculating [itex]\displaystyle\frac{1-z}{z}[/itex] using this fact. The steps for that should be easy enough, just plug in z and simplify to [itex]\displaystyle\frac{\theta^2}{\Omega}[/itex].

I believe the second line after the red text is a typo. It should be [itex]\theta\pi = 1 - z[/itex]. This is easy enough to see by plugging in the formula from the line right below the red text into the formula right above the red text.

Does that help explain it? Also, are little k and big K the same variables? Big K pops up randomly.
 
yes, thank you that helps a lot!

yes the k and the capital K are meant to be the same variable oops :P
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
9
Views
2K
Replies
39
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K