Algebraic Degree of a & b: F(a,b)=mn

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SUMMARY

The discussion centers on the algebraic degree of elements a and b over a field F, specifically addressing the relationship expressed as F(a,b) = mn, where m and n are the degrees of a and b, respectively. It is established that if a and b are algebraic over F and their degrees are relatively prime, then the extension degree [F(a,b):F] equals mn. However, the assertion that [F(a,b):F] equals the product of the individual degrees [F(a):F][F(b):F] is incorrect in general, highlighting the need for careful consideration of the conditions under which this holds.

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Homework Statement



If a and b are algebraic over F of degree m and n, both relatively prime, then

F(a,b)=mn, (i.e. [F(a,b):F]=mn)

any comments are helpfull.
 
Last edited:
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Your post is very incomplete. Are a and b algebraic over a field F? And by "F(a,b)=mn" do you mean "[F(a,b):F]=mn"?

In which case, that m and n are relatively prime is important. Are you trying to say that [F(a,b):F]=[F(a):F][F(b):F]? This is false in general (why?).
 
Last edited:

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