Sorry if this is a well known thing, but I've noticed this and decided to see how well known it is, also if there is a way to prove it other than the recursive series.(adsbygoogle = window.adsbygoogle || []).push({});

a_{n}=(a_{n-1}-a_{n-2}+2)+a_{n-1}

This recursive series will in fact generate every square number. Take in example:

a_{0}=0

a_{1}=1

So if you use the recursive series above:

a_{2}=(a_{1}-a_{0}+2)+a_{1}

a_{2}=(1-0+2)+1

Any comments? I'm praying I used the 'sub' tags right

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# All Square Numbers Follow a Recursive Series?

Loading...

Similar Threads for Square Numbers Follow |
---|

I Can we construct a Lie algebra from the squares of SU(1,1) |

A Last Gauss Lemma Section II |

Least Square basic problem |

B ##AB = I \implies BA = I##, for square matricies ##A,B## |

**Physics Forums | Science Articles, Homework Help, Discussion**