Consider the subset U ⊂ R3[x] defined as

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The discussion focuses on proving that a subset U of degree 3 or lower polynomials with roots at x=0 and x=-1 forms a vector space. Participants explore the necessary conditions for U to be a subspace, including closure under addition and scalar multiplication, and the existence of a zero element. It is established that the sum of two polynomials in U retains the roots at 0 and -1, confirming closure under addition. The conversation also clarifies that scalar multiplication of a polynomial in U by a real number maintains the polynomial's properties, thus confirming closure under scalar multiplication. Finally, the need for a basis and dimension of the vector space is discussed, emphasizing the importance of linear independence and spanning properties.
  • #61
Mark44 said:
The part above is OK.
No. Take a closer look at post #56. I've laid it all out for you, including how to get a set of basis functions.
I have no idea what you're trying to say here.
Basis would be {x^3+x^2,x^3-x}
 
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  • #62
Karl Porter said:
Basis would be {x^3+x^2,x^3-x}
Yes.
Let's call these ##p_1(x)## and ##p_2(x)##, respectively.
As a check that these functions are in U, it would be good to verify that ##p_1(0) = 0, p_1(-1) = 0## and that ##p_2(0) = 0, p_2(-1) = 0##.
 
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