Hans de Vries
Science Advisor
Gold Member
- 1,094
- 31
Alejandro,
I'm trying to go back to more physics but first this. The two
lepton ratio formula's may also be combined into the following:
\ln {m_\tau \over m_\mu} = {\pi-{1 \over \pi}}_______ \ln {m_\mu \over m_e} = {4^2+1 \over 3^2} (\pi-{1 \over \pi})_______\ln {m_\tau \over m_e} = {5^2+1 \over 3^2} (\pi-{1 \over \pi})
Now if and only if the term \pi-1/\pi was exact then all three
formulae would be within experimental range. Now it isn't but the
\pi-1/\pi term is the only thing that I could connect to some real
physics up to now. It's inspired on the way how you rewrote:
\ln {m_\tau \over m_\mu} = {\pi-{1 \over \pi}}\ \ \ \ \ \ \equiv \ \ \ \ \ \ \ln {m_\tau \over m_\mu} = 2\sinh(\ln \pi)\ \ \ \ \ \ \equiv \ \ \ \ \ \ {m_\tau \over m_\mu} = |\exp( \sinh(\ln\pi) )|^2
the sinh() gives us something in the space-time domain or in
momentum space if we consider it to be a boost like in:
\sinh \xi=\frac{ v/c}{\sqrt{1-v^2/c^2}}____\cosh \xi=\frac{1}{\sqrt{1-v^2/c^2}}
with:
\tanh \xi=v/c ____\exp \xi=Doppler Ratio
The Doppler Ratio now becomes \pi interestingly enough (for
blueshift) and 1/\pi (for redshift) corresponding with a speed
v/c (of rotation?) The term \pi-1/\pi could for instance
correspond with the imbalance in momentum change when
absorbing a photon from the back and a photon from the front.
The term |\exp( )|^2 may possibly be associated with going from
phase space (defined in x and ct) to probability space. if the
masses were to be defined as "mass density probabilities"
(mass * wave function) then the imaginary part of the
argument would define phase while the real part would
lead to the mass ratio at each point of the wave function.
Another, although numerological, reason to become interested
in this approach is that the most exact equations I got up to
now are found in the "boost domain", that is:
\ln {m_\mu \over m_e} \ = \ 2\sinh(a) * 1.000000093 ,____\ln {m_\tau \over m_\mu} \ = \ 2\sinh(b) * 1.0000047
with:
a = 1 +\sqrt{1/2} \ \ \ and \ \ \ ab^2 = \sqrt 5
I don't know if a and b are really a pair but at least there is a
simple relationship.
That's the best I can do for sofar in the hope to get some
physical meaning out of it.
Regards. Hans
I'm trying to go back to more physics but first this. The two
lepton ratio formula's may also be combined into the following:
\ln {m_\tau \over m_\mu} = {\pi-{1 \over \pi}}_______ \ln {m_\mu \over m_e} = {4^2+1 \over 3^2} (\pi-{1 \over \pi})_______\ln {m_\tau \over m_e} = {5^2+1 \over 3^2} (\pi-{1 \over \pi})
Now if and only if the term \pi-1/\pi was exact then all three
formulae would be within experimental range. Now it isn't but the
\pi-1/\pi term is the only thing that I could connect to some real
physics up to now. It's inspired on the way how you rewrote:
\ln {m_\tau \over m_\mu} = {\pi-{1 \over \pi}}\ \ \ \ \ \ \equiv \ \ \ \ \ \ \ln {m_\tau \over m_\mu} = 2\sinh(\ln \pi)\ \ \ \ \ \ \equiv \ \ \ \ \ \ {m_\tau \over m_\mu} = |\exp( \sinh(\ln\pi) )|^2
the sinh() gives us something in the space-time domain or in
momentum space if we consider it to be a boost like in:
\sinh \xi=\frac{ v/c}{\sqrt{1-v^2/c^2}}____\cosh \xi=\frac{1}{\sqrt{1-v^2/c^2}}
with:
\tanh \xi=v/c ____\exp \xi=Doppler Ratio
The Doppler Ratio now becomes \pi interestingly enough (for
blueshift) and 1/\pi (for redshift) corresponding with a speed
v/c (of rotation?) The term \pi-1/\pi could for instance
correspond with the imbalance in momentum change when
absorbing a photon from the back and a photon from the front.
The term |\exp( )|^2 may possibly be associated with going from
phase space (defined in x and ct) to probability space. if the
masses were to be defined as "mass density probabilities"
(mass * wave function) then the imaginary part of the
argument would define phase while the real part would
lead to the mass ratio at each point of the wave function.
Another, although numerological, reason to become interested
in this approach is that the most exact equations I got up to
now are found in the "boost domain", that is:
\ln {m_\mu \over m_e} \ = \ 2\sinh(a) * 1.000000093 ,____\ln {m_\tau \over m_\mu} \ = \ 2\sinh(b) * 1.0000047
with:
a = 1 +\sqrt{1/2} \ \ \ and \ \ \ ab^2 = \sqrt 5
I don't know if a and b are really a pair but at least there is a
simple relationship.
That's the best I can do for sofar in the hope to get some
physical meaning out of it.
Regards. Hans
Last edited: