Also help with conicsmainly ellipses?

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SUMMARY

The discussion focuses on converting the equation x² + 4y² - 2x - 32y = 0 into standard form for an ellipse. The solution involves completing the square for both x and y terms, resulting in the equation (x-1)²/65 + (y-4)²/(65/4) = 1. This confirms that the transformation is accurate, leading to the standard form of an ellipse. The final equation indicates the center at (1, 4) with semi-major and semi-minor axes derived from the denominators.

PREREQUISITES
  • Understanding of conic sections, specifically ellipses
  • Knowledge of completing the square technique
  • Familiarity with standard form equations of conics
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the properties of ellipses, including foci and directrices
  • Learn about the derivation of the standard form of conic sections
  • Explore transformations of conic sections in coordinate geometry
  • Practice additional problems involving completing the square for different conic equations
USEFUL FOR

Students studying algebra and geometry, particularly those focusing on conic sections and ellipses, as well as educators seeking to reinforce these concepts in their curriculum.

ilygurlie
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Homework Statement



x^2 + 4y^2 - 2x - 32y = 0
Get into standard form

Homework Equations





The Attempt at a Solution


x^2 + 4y^2 - 2x - 32y = 0
Complete the square two times.
(x^2 - 2x + 1) +4(y^2 - 8y +16 )=0 + 4(16) + 1
Simplfy..
(x-1)^2 + 4(y-4)^2 =65
Try to get the equation to be equal to one.. so divide by 65.
(x-1)^2/(65) + (y-4)^/(65/4) = 1
Did I do this right? This just looks really strange...
 
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It doesn't look strange to me. It looks correct.
 

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