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Also help with conicsmainly ellipses?

  1. Oct 24, 2008 #1
    1. The problem statement, all variables and given/known data

    x^2 + 4y^2 - 2x - 32y = 0
    Get into standard form

    2. Relevant equations



    3. The attempt at a solution
    x^2 + 4y^2 - 2x - 32y = 0
    Complete the square two times.
    (x^2 - 2x + 1) +4(y^2 - 8y +16 )=0 + 4(16) + 1
    Simplfy..
    (x-1)^2 + 4(y-4)^2 =65
    Try to get the equation to be equal to one.. so divide by 65.
    (x-1)^2/(65) + (y-4)^/(65/4) = 1
    Did I do this right? This just looks really strange...
     
  2. jcsd
  3. Oct 24, 2008 #2

    Dick

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    Science Advisor
    Homework Helper

    It doesn't look strange to me. It looks correct.
     
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