Altered die problem (Probability)

  • Context: Undergrad 
  • Thread starter Thread starter bobsz
  • Start date Start date
  • Tags Tags
    Probability
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 3K views
bobsz
Messages
3
Reaction score
0
Hello everyone,

I need some help with the following prob:

A bag contains 3 dice, 2 fair and 1 altered with all odd numbers replace with "1". One die is randomly selected and rolled independently twice. If the outcomes of both rolls were "1" and "1", what is the prob that the selected die is the altered die?

Thanks
 
Physics news on Phys.org
Altere die problem

Here's what I've done:

Let A= Altered die and B=outcome is 1

then P(A|B) = P(A∩B)/ P(B)
P(A∩B) = 1/12 ( outcome of 3 11's)
P(B)= 5/9 ( total outcome of 1's)

therefore P(A|B) = (1/12)/(5/9) = 3/20

Is this correct? Is there another way to approach this problem?

Thanks!