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B field due to a wire with an alternating current

  1. Nov 14, 2009 #1
    1. The problem statement, all variables and given/known data
    I need to find the magnetic field a distance [itex]r[/itex] from a long, thin wire carrying a current [itex]I(t) = I_0 \sin \omega t[/itex].


    2. Relevant equations
    Field a distance [itex]r[/itex] from a wire carrying a steady current [itex]I[/itex] in the [itex]z[/itex] direction:

    [tex]
    \vec B(r) = \frac{\mu_0 I}{2 \pi r} \hat \phi
    [/tex]


    3. The attempt at a solution
    I'm tempted to say that, in the case of the alternating current,

    [tex]
    \vec B(r) = \frac{\mu_0 I_0 \sin \omega t}{2 \pi r} \hat \phi,
    [/tex]

    but I'm not sure I'm right, and I certainly can't explain to myself why it should be Ok to assume that the DC result will be the same as the AC result. My HW problem is actually very complicated: There's a lot of stuff involving induced EMF and time-average power. But I think I'm golden on this problem if I can just figure out what the [itex]\vec B[/itex]-field should be. Thanks!
     
  2. jcsd
  3. Nov 15, 2009 #2

    Delphi51

    User Avatar
    Homework Helper

    I think you are right. Inductance effects will cause the AC potential across the wire to be different from the DC, but you are given current and it directly causes the B field so it shouldn't matter whether DC or AC.
     
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