A circular conducting coil of radius 2.8 cm is placed in a uniform magnetic field of .900 T with the plane of the coil perpendicular to magnetic field. Coil rotated 180 degrees about the axis in .222 seconds. If the coil is made of copper with a diameter of .900 mm, what is the average current that flows through the coil during the rotation?
V = IR R = pL/A
The Attempt at a Solution
I correctly figured out the induced voltage of .02 V.
V = IpL/A
p of copper = 1.68e-7
L = 2pi*r A = pi*r squared so L/A = 2pi*r/pi*r sq. = 2/r
.02 V = I (1.68e-7)(2/.45e-3)
I = .00267e4
The answer per the webassign is 4.32 A. HELP!