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znaya
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Homework Statement



Consider v1 = 30 sin(ωt + 10º) and v2 = 20 cos(ωt - 40º)

A: v1 is in advance to v2
B: v1 differs 50º from v2
C: v2 is in advance to v1
D: v1 is in quadrature to v2

Homework Equations


The Attempt at a Solution



I think the correct answer is A because v1's angle is nearer -∏/2 than v2's.
Does this make any sense?

Thanks for any help.
 
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20 cos(ωt - 40º) = 20 sin(ωt + 50º), right?

v1 is in advance, right?
 
znaya said:
20 cos(ωt - 40º) = 20 sin(ωt + 50º), right?
right! :-p
v1 is in advance, right?

i can never remember which way round "in advance" is :redface:

i'll take your word for it! :smile:
 
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