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**1. Homework Statement**

To find the voltage-current relationship of a capcitor, integrate both sides of

i = C(dv/dt)

**3. The Attempt at a Solution**

In the book they say, v = (1/C)(The Integral from -tve infitity to t) of i dt.

or

v = (1/C)(The Integral from tnot to t) of i dt + v(tnot)

I am trying to understand why they integrated from negative infinity. Why not start the integration at 0. I also do not undersstand in the second equation where the + v(tnot) came from.

Thanks in advance