Aluminium Block immersed in water beaker

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SUMMARY

The discussion centers on the physical principles governing the apparent weight loss of an aluminum block when submerged in water. It establishes that the weight of the aluminum block remains constant in air and water, but the block appears lighter due to the buoyant force acting on it. The relationship between the weight change and the buoyant force is explained through the principles of gravity and buoyancy, confirming that the magnitudes of weight change and buoyant force are equal. This conclusion is supported by the understanding of how buoyancy operates in fluid mechanics.

PREREQUISITES
  • Understanding of buoyancy principles
  • Familiarity with Archimedes' principle
  • Basic knowledge of weight measurement using a spring balance
  • Concept of forces acting on submerged objects
NEXT STEPS
  • Study Archimedes' principle in detail
  • Learn about buoyant force calculations in different fluids
  • Explore the effects of gravity on submerged objects
  • Investigate the relationship between density and buoyancy
USEFUL FOR

Students studying physics, educators teaching fluid mechanics, and anyone interested in understanding the principles of buoyancy and weight measurement in fluids.

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Homework Statement


physical reasons for the relationship between weight change(100CC beaker with water and when you dip aluminum block in water ) and apparent loss in weight of the aluminium (Aluminium block weight using spring balance and when that block immersed in water)

Homework Equations


what is the physical reason for the relationship?
As my lab suggest that both magnitudes are same.

The Attempt at a Solution


I think because they both work in gravity.. the relationship will be same.
 
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You have a system consisting of a block of metal and a tub of water.
The weight of the system in air is the same when the block is outside the water as when it is submerged in the water - all else remaining equal.

If you weigh the metal block by itself - it should appear lighter in water than out of water.

Which situation did you do?

For the situation - consider all the forces that could act on the system being studied.
Hint: how does buoyancy work?
 

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