Amount of charge flowing through a resistor?

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Homework Help Overview

The discussion revolves around calculating the amount of charge flowing through a resistor given a specific current and time, as well as determining the power dissipated in the resistor based on its resistance and current. The subject area includes concepts from electrical circuits, specifically focusing on current, charge, and power calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between current, charge, and time, with some attempting to apply the formula for charge. Questions arise regarding the definitions of current and power, and whether power can be equated to resistance.

Discussion Status

Several participants are actively engaging with the problem, attempting calculations and clarifying definitions. There is a mix of correct and incorrect reasoning, with some guidance provided regarding the units of measurement and the relationships between current, charge, and power. No explicit consensus has been reached.

Contextual Notes

Participants express confusion over the definitions and calculations related to power and charge, indicating a need for further clarification on these concepts. There is also mention of an impending exam, which may influence the urgency of the discussion.

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Amount of charge flowing through a resistor?

the current through a resistor is 3 mA. What charge will flow through it in 200 seconds?

if the resistor has a resistance of 2.0 kΩ what will be the power dissipated in it?

for the first one, i have no idea. i can't seem to find any formula that is relavent to this so I am guess the answer is simple but I am missing a vital piece of information that would link the dots.

for the second one i was thinking the power disippated in the resistor would be the same as the resistance, becuase the resistance is stopping anything above 2.0 V to enter the resistor?

any help is appriated, this is for my exam tomorrow.
 
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druuuuuuuunnk said:
for the first one, i have no idea. i can't seem to find any formula that is relavent to this so I am guess the answer is simple but I am missing a vital piece of information that would link the dots.
What's the definition of current?

for the second one i was thinking the power disippated in the resistor would be the same as the resistance, becuase the resistance is stopping anything above 2.0 V to enter the resistor?
No, power is not the same as resistance. But the power dissipated depends on the current and the resistance. (Look it up!)
 


Doc Al said:
What's the definition of current?

"Electrical current is a measure of the amount of electrical charge transferred per unit time. It represents the flow of electrons through a conductive material.
Current is a scalar quantity (though in circuit analysis, the direction of current is relevant). The SI unit of electrical current is the ampere, defined as 1 coulomb/second"

so its 600 coulombs

im still confused about power, I've tried looking it up but it doesn't make any sense, is it the same as voltage?

so V=IxR

meaning 3 mA x 2 kΩ giving me 6 Volts that are being dissapated in the resistor
 


druuuuuuuunnk said:
"Electrical current is a measure of the amount of electrical charge transferred per unit time. It represents the flow of electrons through a conductive material.
Current is a scalar quantity (though in circuit analysis, the direction of current is relevant). The SI unit of electrical current is the ampere, defined as 1 coulomb/second"
Current = Charge/Time, thus Charge = Current * Time.

so its 600 coulombs
Redo that calculation.

im still confused about power, I've tried looking it up but it doesn't make any sense, is it the same as voltage?
No. Read: http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elepow.html#c2"
 
Last edited by a moderator:


Ok so, to find the charge in 200 seconds. I multiply 3mA by 200 because charge = current*time

Giving me 600A ??

And for the second part I use Power = voltage * current

So the power dissipated in the resistor = 600 (current) * 2 (resistance) is this wrong ?
 


Actually for the second part, I'm meant to use power = current squared * resistance. So I'd get 720,000
 


druuuuuuuunnk said:
Ok so, to find the charge in 200 seconds. I multiply 3mA by 200 because charge = current*time

Giving me 600A ??
Careful: mA means milli-Amps = 10-3 Amps

(And the charge would be in Coulombs, not Amps.)

Same issue with your power calculation.
 


Ok, cheers mate!
 

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