Amplitude of a mass joined to a spring in the presence of an E-field

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SUMMARY

The discussion focuses on calculating the amplitude of simple harmonic motion (SHM) for a mass connected to a spring in the presence of a horizontal electric field. The key equation used is qE = kx, which equates the electric force to the spring force at the extreme positions of the motion. The conservation of energy approach was initially attempted but deemed incomplete by participants. The correct method involves recognizing that the forces are balanced at maximum displacement, leading to the conclusion that amplitude can be directly derived from the force equilibrium.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM)
  • Knowledge of Hooke's Law and spring constant (k)
  • Familiarity with electric fields and force equations (F = qE)
  • Basic principles of energy conservation in mechanical systems
NEXT STEPS
  • Study the derivation of amplitude in SHM using force equilibrium methods
  • Learn about the relationship between electric fields and forces on charged objects
  • Explore the implications of energy conservation in oscillatory systems
  • Investigate the effects of varying spring constants on amplitude in SHM
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and electromagnetism, as well as educators looking for clarification on SHM in electric fields.

Shivang kohlii
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Homework Statement


A block of mass m having charge q placed on smooth horizontal table and is connected to a wall thorough an unstretched spring of constant k . A horizontal electric field E parallel to spring is switched on. Find the ampliture of the shm by the block.

Homework Equations


kx= qe
U of spring= 1/2kx[2][/SUP]

The Attempt at a Solution


Using conservation of energy and work done by field ,F = qEx
1/2kx^2 = qEx
X (amplitude ) = 2qE/x
But ans isn't this..
In answer directly the forces have been equated
qE = kx
.. I don't understand why has this equation been used to calculate amplitude when conservation of energy is used to calculate the maximum displacement of a body attached to spring when moved from equilibrium position in ?
 
Last edited:
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Your problem statement is very incomplete. Could you copy the exact wording ? The way it is formulated now the right answer could as well be the amplitude of the electric field: E !

Your conservation of energy equation is incomplete and F = qEx looks misleading.
 
BvU said:
Your problem statement is very incomplete. Could you copy the exact wording ? The way it is formulated now the right answer could as well be the amplitude of the electric field: E !

Your conservation of energy equation is incomplete and F = qEx looks misleading.

I don't understand how to write the conservation of energy equation for this case
 
BvU said:
Your problem statement is very incomplete. Could you copy the exact wording ? The way it is formulated now the right answer could as well be the amplitude of the electric field: E !
:smile: It is standard to minimize effort: if something is asked and something else is commented, you ignore the request and comment on the comment.
I realize you have difficulty with this exercise and I am trying to help.
Start with a clear problem description.
If you think you need energies, you should list some energy equations as well.

Is it clear to you what the situation is ? Do you have enough information ?
What is actually happening when E is switched on and what is asked of you (in particular: the amplitude of what?) ? Did you make a sketch ?
 
Shivang kohlii said:
In answer directly the forces have been equated
qE = kx
.. I don't understand why has this equation been used to calculate amplitude when conservation of energy is used to calculate the maximum displacement of a body attached to spring when moved from equilibrium position in ?
The problem has been correctly solved by equating ##qE=kx##.
This eqn applies only when the body is at the extreme positions, as then it has no acceleration ## (a)## there.
In all other positions in between, the eqn of motion is ##qE\pm ma=kx##.
 
What does Shivang have to say ?
 

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