Amplitude of equation of motion

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The discussion centers on determining the amplitude of a forced oscillation described by the equation mx_double_dot + rx_dot + kx = Pcos(Ωt). The user seeks to find the frequency (Ω) to calculate the amplitude but realizes that the system is overdamped, which affects the oscillation behavior. It is noted that the absence of a driving frequency does not prevent finding the amplitude envelope, which is characterized by a decaying exponential. The conversation emphasizes the importance of identifying the natural frequency and damping ratio to simplify the analysis. Ultimately, the amplitude can be determined without the driving frequency by comparing the equation to general solutions of driven harmonic oscillators.
jimmy42
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Hello,

I have worked out some force diagrams for forced oscillations and ended up with the solution as :

mx_double_dot+rx_dot+kx=Pcos(Ωt)

I am now asked to work out the amplitude. I know all of the variables except frequency(Ω). What equations can I use to find that?

Thanks.
 
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m\ddot{x}+r\dot{x}+kx=P\cos(\omega t)
... to see how the amplitude behaves, you'll need to solve the equation.
The driving frequency is something you'd normally be given.

I don't see a damping term - what do you think is likely to happen to the amplitude of the oscillations?
 
I have worked out that this is a strongly dampered equation, so I expect the amplitude to die down quickly.

So, without frequency, this cannot be done? The question I have is to get the amplitude in order to solve the frequency between certain amplitudes. That last part can be done on the computer.
 
Oh I misread it - OK. So you have determined the system is overdamped which simplifies things - you need to find the natural frequency and damping ratio.

You don't need the driving frequency to find the amplitude envelope - it's a decaying exponential: compare your equation with the general solutions.
http://en.wikipedia.org/wiki/Harmonic_oscillator#Driven_harmonic_oscillators
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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