An electric dipole consists of a pair of equal but opposite charges

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SUMMARY

An electric dipole consists of two equal but opposite charges, +Q and -Q, separated by a distance d. The electric potential at the midpoint between these charges is calculated using the formula electric potential = kQ/r, resulting in a value of 0 V. This value indicates that while the potential energy at this point is zero, the forces acting on a test charge placed there are determined by the electric field gradient, not the absolute potential. The discussion emphasizes that electric potential is relative, and the reference point for measuring potential can be chosen arbitrarily, commonly set to zero at infinity.

PREREQUISITES
  • Understanding of electric dipoles and charge interactions
  • Familiarity with the formula for electric potential: V = kQ/r
  • Knowledge of electric fields and their gradients
  • Concept of potential difference and reference points in electrostatics
NEXT STEPS
  • Study the concept of electric field gradients and their relationship to electric potential
  • Learn about potential difference and how it is measured between two points
  • Explore the implications of choosing different reference points for electric potential
  • Investigate the behavior of test charges in electric fields created by dipoles
USEFUL FOR

Students of physics, educators teaching electrostatics, and anyone interested in understanding electric dipoles and their properties.

needingtoknow
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Homework Statement



An electric dipole consists of a pair of equal but opposite charges, +Q and -Q separated by a distance d. What is the electric potential at the point that's midway between these source charges?

Through using the formula electric potential = kQ/r, I found the electric potential at P to be 0. Electric potential is the amount of potential energy each coulomb of charge would possesses in an electric field right, so then why is it 0. If I place a negative charge at Point P, won't it be attracted to the +ve charge and repel by the negative charge. Won't it use potential energy to accelerate towards the +ve charge?
 
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needingtoknow said:
I found the electric potential at P to be 0. Electric potential is the amount of potential energy each coulomb of charge would possesses in an electric field right, so then why is it 0. If I place a negative charge at Point P, won't it be attracted to the +ve charge and repel by the negative charge. Won't it use potential energy to accelerate towards the +ve charge?
You're confusing potential with gradient of potential. The field is the gradient of the potential, and this is what causes the force on a test charge.

I don't like the question, though. Potentials are not absolute. It's only potential difference that matters. You can take the potential at any point to be your reference potential (zero) and measure all other potentials in relation to it. The question only works if you specify also that the potential at infinity is zero.
 
Does it matter that the point is 0 V only relative to other points as well. I don't think I am asking the question correctly, so I have attached a picture of the question which has the diagram too. It is part b).
 

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needingtoknow said:
Does it matter that the point is 0 V only relative to other points as well.
Not exactly sure what you are asking there.
There is nothing special about 0V, it's an arbitrary reference point. As the attachment states, what matters is potential difference, i.e. the difference in voltage between two points.

The attachment says the diagram shows "the electric potential at various points in the field they produce". That's a little misleading, because you could add some constant to every value and it would be effectively the same. On the other hand, it is customary to set the 0 V level as the potential "at infinity", which is perhaps assumed here. Or, equivalently, you could interpret the statement as meaning the charges add those potentials to an assumed background potential of zero everywhere.
 

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