An elementary question about rotations

[Silicon-Based]

TL;DR

Rotation of spin-1/2 state

Suppose I have a positive spin-$1/2$ eigenstate pointing in the $z$-direction. If I apply a rotation operator by an angle $\theta$ around the $z$-axis the state should of course not change. However, if I write it out explicitly, I find something different:
$$R_z(\theta)|\uparrow\rangle =
\begin{pmatrix}
e^{-i\theta/2} & 0 \\
0 & e^{i\theta/2}
\end{pmatrix}
\begin{pmatrix}
1 \\
0
\end{pmatrix} =
e^{-i\theta/2}|\uparrow\rangle.
$$Is this factor of $e^{-i\theta/2}$ like a phase that can be added and removed at will because it's not an observable? I don't see a different way to rationalize this with the physical expectation above.

 

[PeroK]

Summary: Rotation of spin-1/2 state

Suppose I have a positive spin-$1/2$ eigenstate pointing in the $z$-direction. If I apply a rotation operator by an angle $\theta$ around the $z$-axis the state should of course not change. However, if I write it out explicitly, I find something different:
$$R_z(\theta)|\uparrow\rangle =
\begin{pmatrix}
e^{-i\theta/2} & 0 \\
0 & e^{i\theta/2}
\end{pmatrix}
\begin{pmatrix}
1 \\
0
\end{pmatrix} =
e^{-i\theta/2}|\uparrow\rangle.
$$Is this factor of $e^{-i\theta/2}$ like a phase that can be added and removed at will because it's not an observable? I don't see a different way to rationalize this with the physical expectation above.

As you say, the value of all observables measured on that state will not change. However, rotating the system has changed the state. Note, for example, that rotating the system by $2\pi$ results in a phase factor of $-1$. In QM you have to rotate a system by $4\pi$ to return to the original state.

Note that this is a general result for rotations of systems in QM. Not just spin 1/2 particles.

This prediction of QM can be tested. There is an experiment quoted in Sakurai, for example, using neutron interferometry. The idea is to split a beam of neutrons, with one path involving a rotation and then to recombine the paths and observe the interference pattern.

If one path involves a rotation of $2\pi$ you should see destructive interference, but not for a rotation of $4 \pi$.

 

[hilbert2]

If I have a system of two unentangled spins, with state vector like $\left|\right.\uparrow\rangle\left|\right.\uparrow\rangle$, would a rotation of $2\pi$ add a factor of -1 or would the minus signs from the two spins cancel? Just a thought that came to my mind and it's not immediately clear to me what happens...