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\left(x^2-1\right)\frac{d}{dx}\left(x^2-1\right)^n = 2nx\left(x^2-1\right)^{n-1}

$$? This is in a textbook and says that its proof is left as an exercise. It seems to be a difficult equality.

I believe this should just be $$

\left(x^2-1\right)\frac{d}{dx}\left(x^2-1\right)^n = 2nx\left(x^2-1\right)^{n}

$$ by simple differentiation.

Am I wrong or not?

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# An equality about derivative of a polynomial?

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