An equality about derivative of a polynomial?

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SUMMARY

The equality $$\left(x^2-1\right)\frac{d}{dx}\left(x^2-1\right)^n = 2nx\left(x^2-1\right)^{n-1}$$ is confirmed as correct through the application of the product rule in calculus. The confusion arises from a misunderstanding of the differentiation process, where the term $$\left(x^2-1\right)^{n}$$ is mistakenly suggested instead of the correct $$\left(x^2-1\right)^{n-1}$$. This equality is a standard result in polynomial differentiation and is often left as an exercise in textbooks.

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td21
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Why is $$
\left(x^2-1\right)\frac{d}{dx}\left(x^2-1\right)^n = 2nx\left(x^2-1\right)^{n-1}
$$? This is in a textbook and says that its proof is left as an exercise. It seems to be a difficult equality.

I believe this should just be $$
\left(x^2-1\right)\frac{d}{dx}\left(x^2-1\right)^n = 2nx\left(x^2-1\right)^{n}
$$ by simple differentiation.

Am I wrong or not?
 
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td21 said:
Why is $$
\left(x^2-1\right)\frac{d}{dx}\left(x^2-1\right)^n = 2nx\left(x^2-1\right)^{n-1}
$$? This is in a textbook and says that its proof is left as an exercise. It seems to be a difficult equality.

I believe this should just be $$
\left(x^2-1\right)\frac{d}{dx}\left(x^2-1\right)^n = 2nx\left(x^2-1\right)^{n}
$$ by simple differentiation.

Am I wrong or not?
What you have seems fine to me, but I can't say that the book is wrong without actually seeing what is in the book.
 

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