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An equilateral triangle w/3 =forces, 1/side,why is sum of torques always= at any pt?

  1. Oct 20, 2008 #1
    1. The problem statement, all variables and given/known data

    and why is it FLcos(30)?

    2. Relevant equations



    3. The attempt at a solution
    So by looking at the soln, D(distance)=Lcos(30), which should be the hieght of the traingle. But the distances between a the forces at any point don't always add up to the hieght.. Im confused
     
  2. jcsd
  3. Oct 21, 2008 #2

    alphysicist

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    Re: An equilateral triangle w/3 =forces, 1/side,why is sum of torques always= at any

    Hi mistymoon_38,

    Could you provide more details about how the triangle and the forces are setup (are the forces acting on the midpoints of the sides, going out, or something else)? and about the calculation that you are talking about (as in where is the pivot point for the torque equation)?
     
  4. Oct 21, 2008 #3
    Re: An equilateral triangle w/3 =forces, 1/side,why is sum of torques always= at any

    i figured it out on my own. thanks anyways
     
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