An identity to prove using calculus 1

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Homework Help Overview

The discussion revolves around proving an identity involving a function defined in terms of an integral and its derivative. The subject area includes calculus, specifically the application of the Fundamental Theorem of Calculus and differentiation techniques.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the need to differentiate the function and question whether all necessary components were copied correctly. There is discussion about the conditions on the function A(x) and its differentiability, as well as the implications of the Fundamental Theorem of Calculus in the context of the problem.

Discussion Status

Participants are actively engaging with the problem, raising questions about the completeness of the information provided and the assumptions regarding the function A(x). Some guidance is offered regarding the need for derivatives and the application of calculus principles, but no consensus on a solution has been reached.

Contextual Notes

There is a lack of explicit conditions specified for A(x) by the teacher, leading to some uncertainty among participants about the assumptions that can be made. The context of the problem being part of a timed exercise adds to the pressure of finding a solution.

0kelvin
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Homework Statement
There is this function $$f(x) = e^{-A(x)} + e^{-A(x)} \int_0^x t e^{A(t)} dt$$

I have to prove that f satisfies $$f(x) + e^{-x^2} f(x) = x$$
Relevant Equations
$$A(x) = \int_0^x e^{-y^2} dy$$
I have a feeling that I forgot to copy something from the black board, maybe some f' because as it is I'm not seeing a solution.
 
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I agree, I think one of those ##f(x)## terms in the thing you're supposed to prove is probably ##f'(x)##

I would start by taking the derivative of ##f(x)## with respect to ##x##. That means you're going to need the Fundamental Theorem of Calculus in a couple of places.
 
Ah right. ##f'(x) + e^{-x^2}f(x) = x##.

Doing all the calculatiosn right, I'll end up with ## xe^{A(x) - A(x)} = x ##. Some chain and ´product rule here and there.
 
0kelvin said:
Homework Statement: There is this function $$f(x) = e^{-A(x)} + e^{-A(x)} \int_0^x t e^{A(t)} dt$$

I have to prove that f satisfies $$f(x) + e^{-x^2} f(x) = x$$
Homework Equations: $$A(x) = \int_0^x e^{-y^2} dy$$

I have a feeling that I forgot to copy something from the black board, maybe some f' because as it is I'm not seeing a solution.
Sorry to nitpick, but , any conditions on A(x)? Continuity, differentiability, etc? Most likely even nicer, but just for the sake of completeness.
 
Teacher didn't specify. For some reason he thought it would be a good idea to give everyone 15 minutes to solve it last week. Solving it would give up to +1 point in the next exam.
 
0kelvin said:
Teacher didn't specify. For some reason he thought it would be a good idea to give everyone 15 minutes to solve it last week. Solving it would give up to +1 point in the next exam.
But in order to differentiate, you would need to know something about A(t). I guess it is assumed that it is nice-enough to be differentiable.
 
WWGD said:
But in order to differentiate, you would need to know something about A(t). I guess it is assumed that it is nice-enough to be differentiable.
It is given that ##A(x)=\int_0^x e^{-y^2}dy## it is listed under homework equations tab in OP.
 
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Delta2 said:
It is given that ##A(x)=\int_0^x e^{-y^2}dy## it is listed under homework equations tab in OP.
My bad, did not pay attention.
 

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