An identity to prove using calculus 1

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The discussion revolves around proving that the function f(x) satisfies the equation f(x) + e^(-x^2) f(x) = x, with f(x) defined as e^(-A(x)) + e^(-A(x)) ∫_0^x t e^(A(t)) dt. Participants emphasize the need to differentiate f(x) using the Fundamental Theorem of Calculus and the chain and product rules. There is a concern about the conditions on A(x), specifically its continuity and differentiability, although it is assumed to be differentiable. The problem was assigned as a challenge for extra credit, but clarity on A(x) was lacking initially.
0kelvin
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Homework Statement
There is this function $$f(x) = e^{-A(x)} + e^{-A(x)} \int_0^x t e^{A(t)} dt$$

I have to prove that f satisfies $$f(x) + e^{-x^2} f(x) = x$$
Relevant Equations
$$A(x) = \int_0^x e^{-y^2} dy$$
I have a feeling that I forgot to copy something from the black board, maybe some f' because as it is I'm not seeing a solution.
 
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I agree, I think one of those ##f(x)## terms in the thing you're supposed to prove is probably ##f'(x)##

I would start by taking the derivative of ##f(x)## with respect to ##x##. That means you're going to need the Fundamental Theorem of Calculus in a couple of places.
 
Ah right. ##f'(x) + e^{-x^2}f(x) = x##.

Doing all the calculatiosn right, I'll end up with ## xe^{A(x) - A(x)} = x ##. Some chain and ´product rule here and there.
 
0kelvin said:
Homework Statement: There is this function $$f(x) = e^{-A(x)} + e^{-A(x)} \int_0^x t e^{A(t)} dt$$

I have to prove that f satisfies $$f(x) + e^{-x^2} f(x) = x$$
Homework Equations: $$A(x) = \int_0^x e^{-y^2} dy$$

I have a feeling that I forgot to copy something from the black board, maybe some f' because as it is I'm not seeing a solution.
Sorry to nitpick, but , any conditions on A(x)? Continuity, differentiability, etc? Most likely even nicer, but just for the sake of completeness.
 
Teacher didn't specify. For some reason he thought it would be a good idea to give everyone 15 minutes to solve it last week. Solving it would give up to +1 point in the next exam.
 
0kelvin said:
Teacher didn't specify. For some reason he thought it would be a good idea to give everyone 15 minutes to solve it last week. Solving it would give up to +1 point in the next exam.
But in order to differentiate, you would need to know something about A(t). I guess it is assumed that it is nice-enough to be differentiable.
 
WWGD said:
But in order to differentiate, you would need to know something about A(t). I guess it is assumed that it is nice-enough to be differentiable.
It is given that ##A(x)=\int_0^x e^{-y^2}dy## it is listed under homework equations tab in OP.
 
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Delta2 said:
It is given that ##A(x)=\int_0^x e^{-y^2}dy## it is listed under homework equations tab in OP.
My bad, did not pay attention.
 

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