Analysis: Prove |x|+|y| is less than or equal to |x+y|+|x-y|

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SUMMARY

The discussion focuses on proving the inequality |x| + |y| ≤ |x+y| + |x-y| using the triangle inequality. Key equations referenced include |x+y| ≤ |x| + |y| and |x-y| ≤ |x| + |y|. The participants explore various substitutions, including x = u + v and y = u - v, to simplify the proof. The conversation emphasizes the importance of manipulating absolute values and inequalities to establish the desired result.

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Homework Statement



Using the triangle inequality, establish that:

|x| + |y| \leq |x+y| + |x-y|

Homework Equations



|x + y| \leq |x| + |y|

The Attempt at a Solution



I have tried a few things, here are those that seem like they would be most useful:

|x + y| \leq |x| + |y|

\leq |x+y-y| + |y-x+x|

\leq |x+y| + |-y| + |y-x| + |x|

\leq |x+y| + |y| + |y-x| + |x| ...Note that |y-x| = |x-y|

Also,

|x-y| \leq |x| + |-y| = |x| + |y|

which might be able to be used in the middle inequality above.

I'm not sure what to do from here (or if I'm on the right track)
 
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Hi Chinnu! :smile:

Try substituting x=u+v and y=u-v.
Note that you can find a u and a v for any x and y.
 

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