Analytic mechanic, disk and rod

  • Thread starter Thread starter loreberto911
  • Start date Start date
  • Tags Tags
    Disk Mechanic Rod
loreberto911
Messages
4
Reaction score
0
< Mentor Note -- thread moved to HH from the technical engineering forums, so no HH Template is shown >[/color]

?temp_hash=6ae0d015ab67fa1fdbc0d76c05711e87.jpg

A rod rolls without creep. And the disk rolls without creep on Q. The rod can just moves on y. Which is the relation among Va and Vohm?
Va= velocity in A
My resolution:
in Q we know that velocity is zero.Q is also the instant rotation center ( disk).so the P point ( disk) is the fastest. How to bound speed in
##\Omega## and Va?
I mean, just seeing the picture, without using the fondant formula of rigid cinematic. I could think it's like the half of Va.
Ps.it's my first article and my english isn't so good, I hope you'll understand anyway.
 

Attachments

  • PicsArt_1429821096887.jpg
    PicsArt_1429821096887.jpg
    23.1 KB · Views: 526
Last edited by a moderator:
Physics news on Phys.org
Your picture does not define point P very well. Is it the top of the disk, or is it the tangent point? If it is the tangent point (as I suspect), it is "not the fastest point." The "fastest point" is directly on the top.

This is a kinematics problem, and as such, you need to define some more variables and write the suitable relations among them. Define a variable name for the height of point A, a variable for the distance from A to the tangent point (P?), and the angle of the bar with respect to the horizontal. Then write the equations defining the closed loop from the origin to A to P to the center of the disk to Q and back to the origin; there will be two such equations. These can be solved for what you need.
 
OldEngr63 said:
Your picture does not define point P very well. Is it the top of the disk, or is it the tangent point? If it is the tangent point (as I suspect), it is "not the fastest point." The "fastest point" is directly on the top.

This is a kinematics problem, and as such, you need to define some more variables and write the suitable relations among them. Define a variable name for the height of point A, a variable for the distance from A to the tangent point (P?), and the angle of the bar with respect to the horizontal. Then write the equations defining the closed loop from the origin to A to P to the center of the disk to Q and back to the origin; there will be two such equations. These can be solved for what you need.

Thanks for reply,
Point P is tangent, the question that teacher asked to me was "give me a qualitative consideration of velocity in ##\Omega##"
For example the direction, and approximately the entity like "it's 1/3...2/3 of Va". The problem gives me just Va and nothing else. I tried to set problem analytically but professor said no.
 
Afraid I can't help you if a proper mathematical formulation is not allowed.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
6
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
4K
Replies
2
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
3
Views
2K
  • · Replies 22 ·
Replies
22
Views
5K