Analytical Expressions for Frequency Response

Click For Summary
The discussion centers on understanding the mathematical transformation of the function r(t) = Acos(wt) + Bsin(wt) into its phasor representation, which simplifies to sqrt(A^2 + B^2)cos(wt - arctan(B/A). The author explains that this transformation involves using rectangular phasor form and Euler's formula for simplification. Additionally, the focus is on the forced response R(s) derived from the Laplace transform, with an emphasis on the assumption of a linear time-invariant system where transient responses are negligible. The partial fraction expansion technique is discussed as a method to isolate poles of a rational function, which relate to the growth or decay rates of the system's response. Understanding these concepts is crucial for analyzing frequency response in linear systems.
MarkDECE
Messages
1
Reaction score
0
Hi,

I am struggling to understand the maths in the text shown below.

(1) How does: r(t) = Acos(wt)+Bsin(wt)
become; sqrt((A^2)+(B^2))cos(wt - arctan(B/A))?

(2) He states that we can represent the input as a phasor and in one of three ways but doesn't say which one.

(3) He then focus on the forced response {R(s)} the laplace transform of the input.

(4) He then then separates the forced solution from the transient solution by performing a partial faction expansion but I am unsure what is meant by this separation?

Any help genuinely appreciated.
upload_2015-12-17_22-30-21.png

upload_2015-12-17_22-30-58.png

upload_2015-12-17_22-31-20.png
 
Engineering news on Phys.org
1) First write r(t) in rectangular phasor form:
r(t)=Acos(wt)+Bsin(wt)
=Re{A exp(jwt)}-Re{jB exp(jwt)}
=Re{(A-jB) exp(jwt)}
=Re{sqrt(A^2+B^2) exp(-jarctan(B/A)) exp(jwt)}
=sqrt(A^2+B^2)cos(wt-arctan(B/A) //

2) You can see from 1) that I started in trignometric, went to rectangular then used Euler's formula and a property of exponentials to simplify. This can also be done with trig identities but there are extra steps and since you have a linear system this is an easier approach anyways.

3) I believe the author has implicitly assumed a linear time invariant system, G(s), which is stable and hence the transient contribution is negligible in the long term therefore he focuses on the sinusoidal steady-state response only, C_ss(s).

4) partial faction expansion is a method to isolate the "poles" of a rational function. Remeber the location of the poles are growth (or decay) rates of the exponential functions in the time-domain. Incidentally in this example the poles s=+-jw are associated with the output (and input) frequency since sinusoids are the eigenfunctions of LTI systems.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

Similar threads

Replies
6
Views
5K
  • · Replies 17 ·
Replies
17
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
10
Views
3K
Replies
1
Views
11K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 21 ·
Replies
21
Views
6K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
1
Views
2K
  • · Replies 23 ·
Replies
23
Views
4K