Impulse response from frequency response

Click For Summary
SUMMARY

The discussion focuses on deriving the impulse response from a given frequency response that includes both a sinc function and an exponential function. The impulse response is determined using the Inverse Fourier Transform (IFT) of the transfer function, represented as h_0(t) = F^(-1)[H(jω)]. The output y(t) is calculated using the convolution of the input r(t) with the impulse response H(t). The user seeks clarification on the correct application of these methods and the simplification of their approach.

PREREQUISITES
  • Understanding of Inverse Fourier Transform (IFT)
  • Knowledge of sinc function properties
  • Familiarity with convolution in time and frequency domains
  • Basic principles of Laplace transforms
NEXT STEPS
  • Study the properties of the sinc function in signal processing
  • Learn about the application of Laplace transforms in deriving impulse responses
  • Research convolution techniques for combining signals in both time and frequency domains
  • Explore the relationship between frequency response and impulse response in linear systems
USEFUL FOR

Students and professionals in electrical engineering, signal processing, and control systems who are working on deriving impulse responses and analyzing system outputs using Fourier and Laplace transforms.

aguntuk
Messages
7
Reaction score
0

Homework Statement



I am having some problems to derive Inverse Fourier transform of sinc function & exponential function. It's actually for getting the Impulse response from the given frequency response [which comprises of both sinc function & exponential function]. Also need to know the output y(t) for the given input. Can anyone help me out?

The question is in the attachment.

Homework Equations



(a) The impulse response is the inverse transform [IFT] of the transfer function. I think IFT will lead me to get the impulse response.

(b)

The Attempt at a Solution



Solution:

(a)

I stepped forwards as following:

h_0 (t)= F^(-1) [H(jω)]
= 1/2π ∫_(-∞)^(+∞)▒〖T_1 . e^(-jω T_1/2) . sin⁡〖ω T_1/2〗/(ω T_1/2)〗 .〖 e〗^(-jωt) dω
= T_1/2π ∫_(-∞)^(+∞)▒〖e^(jω(t-T_1/2)) dω .∫_(-∞)^(+∞)▒sin⁡〖ω T_1/2〗/(ω T_1/2)〗 dω
= T_1/2π δ(t-T_1/2) ∫_(-∞)^(+∞)▒sin⁡〖ω T_1/2〗/(ω T_1/2) dω

I could not get the sinc function [sin⁡〖ω T_1/2〗/(ω T_1/2)] to Fourier transform and also the derivation from time lapse exponential function [e^(jω(t-T_1/2))] to delta function [δ(t-T_1/2)]. Can anyone help me out the full derivatives of the problem?(b) Is it the right equation to get the system output y (t) as follows?

y(t)= r(t)*[H(jω)]
= A T_1 . e^(-jω T_1/2) . sin⁡〖ω T_1/2〗/(ω T_1/2)
= A T_1 . e^(-jω T_1/2) . sinc(ω T_1/2)

Is the approach ok? And how can it be more simplified?
 

Attachments

  • ImpulseResonse_Freq Response.jpg
    ImpulseResonse_Freq Response.jpg
    15.3 KB · Views: 608
Last edited by a moderator:
Physics news on Phys.org
I'm having a little bit of trouble following your work, so I am going to make some quick comments.

for part a. typically it is easier to use Laplace (at least for me). If you don't know laplace then i guess your method is ok. note: i did not check your work for part a. the method is correct. the work may not be.

for part b. You are mixing the frequency and time domain, so your method is invalid.

y(jw)=r(jw).H(jw)
or
y(t)=r(t)*H(t)

H(t)= impulse response of system.
if you are working in the time domain you use convolution to combine the r(t) and H(t) signal. if you are working in the frequency domain you can simply use multiplication.

not r(t)=A*(u(t)-u(t-T))
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
2K
Replies
1
Views
2K
  • · Replies 17 ·
Replies
17
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 18 ·
Replies
18
Views
7K