Graduate How to Derive a Closed Form for a Double Sum with Stochastic Variables?

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SUMMARY

This discussion focuses on deriving a closed form for a double sum involving stochastic variables, specifically Gaussian-distributed particle velocities denoted as #u_i#. The equation presented involves sums of cosine and sine functions, with constants #U# and #T# representing motion parameters rather than temperature. The approximation for large #N_i# under random sampling leads to a simplified expression involving averages of cosine functions. The context suggests applications in likelihood equations related to discrete Fourier transforms (DFT) in particle motion analysis.

PREREQUISITES
  • Understanding of Gaussian distributions, specifically #u_i \sim \mathcal{N}(\mu_{u}, \sigma_{u})#
  • Familiarity with double summation techniques in mathematical analysis
  • Knowledge of discrete Fourier transforms (DFT) and their applications
  • Basic concepts of particle motion and statistical mechanics
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  • Study the derivation of closed forms for double sums involving stochastic variables
  • Learn about the properties and applications of Gaussian distributions in statistical mechanics
  • Explore the implications of discrete Fourier transforms (DFT) in analyzing particle motion
  • Investigate the relationship between time steps and particle velocities in stochastic processes
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Mathematicians, physicists, and data scientists working with stochastic processes, particularly those analyzing particle dynamics and seeking to derive closed forms for complex summations.

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I have a equation with a double sum. However, one of the variables in one of the sums comes from a stochastic distribution (Gaussian to be specific). How can I get a closed form equivalent of this expression? The U and Tare constants in the equation.

$$ \sum_{k = 0}^{N_k-1} \bigg [ \big[ \sum_{i}^{N_i} \cos(\frac{4\pi}{\lambda} u_i k T) - \cos(\frac{4\pi}{\lambda} U k T) \big]^2 + \big[ \sum_{i = 1}^{N_i} \sin(\frac{4\pi}{\lambda} u_i k T) - \sin(\frac{4\pi}{\lambda} U k T) \big]^2 \bigg]$$

$$ u_i \thicksim \mathcal{N}(\mu_{u}, \sigma_{u}) $$
 
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I do not see what is ##u_i## as a function of number i.
 
anuttarasammyak said:
I do not see what is ##u_i## as a function of number i.
The values of ##u_i## come from a Gaussian Distribution I explain in the second equation. It is a random sample drawn from the same distribution.
 
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Expecting that average including sin is zero, the formula would become
N_i^2 \sum_k <\cos u, k>^2 - 2N_i \sum_k <\cos u,k> (\cos U,k)+ N_k
approximately for large N_i under random sampling for Gaussian distribution where
##<\cos u, k> ## is average of the cos u function given for i samplings with given constant k.
with ##<sin, k>=0##
 
Wondering what sort of problem gave you this monster sums. Let me guess something about the velocities of molecules of a gas at temperature T and internal energy U?
 
Delta2 said:
Wondering what sort of problem gave you this monster sums. Let me guess something about the velocities of molecules of a gas at temperature T and internal energy U?
You almost got it. These are particle velocities #u_i#, but the other parameters are related to motion rather than temperature. #T# is the time step, #k# is the time index. This is sort of a likelihood (DFT) equation where the cyclic velocity (frequency) is #U#. It actually comes from a complex exponential expression, where I have separated the real and the imaginary parts (cos and sin) to have a better function for likelihood. #N_i# are the number of particles and #N_k# are the number of time steps.
 
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