Analyze the reaction in terms of constituent quarks

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SUMMARY

The discussion focuses on the reaction involving constituent quarks, specifically identifying the presence of 2 down quarks (2d), 1 up quark (1u), and 0 strange quarks (0s) post-reaction. The confusion arises from the presence of s quarks in the resulting particles, yet the net strange quark number remains zero due to the presence of one strange and one antistrange quark, balancing the equation. This indicates that the reaction is feasible through the strong interaction, as the net quark numbers do not change.

PREREQUISITES
  • Understanding of quark types: up (u), down (d), and strange (s) quarks
  • Familiarity with the concept of quark number conservation
  • Knowledge of strong interactions in particle physics
  • Basic grasp of particle-antiparticle pairs
NEXT STEPS
  • Research the principles of quark confinement in Quantum Chromodynamics (QCD)
  • Study the role of strong interactions in particle reactions
  • Explore particle-antiparticle annihilation and its implications
  • Learn about the classification of baryons and mesons based on quark composition
USEFUL FOR

Students and researchers in particle physics, physicists specializing in quantum mechanics, and anyone interested in the fundamental interactions of matter at the subatomic level.

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Homework Statement
Analyze the reaction in terms of constituent quarks.
Relevant Equations
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1610158853321.png
 

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mfb said:
Looks fine.
Thanks for your reply. The correct answer in the book is that there are 2d, 1u, and 0s quarks after the reaction. I understand that the strange number is zero but how can you say 0s if the 2 particles formed contain s quarks? Very confusing.
 
The net is zero: One strange, one antistrange. 1+(-1)=0. As that net number didn't change for any quark the process is possible via the strong interaction.
 

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