Analyzing Displacement, Velocity, and Acceleration of a Bicyclist in a Park

  • Thread starter Thread starter mimsteel
  • Start date Start date
  • Tags Tags
    Vectors
Click For Summary
SUMMARY

The discussion focuses on analyzing the displacement, average velocity, and average acceleration of a bicyclist moving in a park. Initially, the bicyclist is positioned 40.0m east of a flagpole, traveling south at 10.0m/s. After 30.0 seconds, the bicyclist is now 40.0m north of the flagpole, moving east at the same speed. Key calculations involve determining the magnitude and direction of displacement, average velocity, and average acceleration using the equations v=d/t and a=(v2-v1)/t.

PREREQUISITES
  • Understanding of vector displacement
  • Knowledge of average velocity calculations
  • Familiarity with average acceleration concepts
  • Proficiency in basic kinematics equations
NEXT STEPS
  • Calculate the magnitude and direction of displacement using vector analysis
  • Determine the average velocity vector from initial to final position
  • Analyze average acceleration using initial and final velocities over time
  • Explore graphical representation of motion in two dimensions
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding motion analysis in two-dimensional space.

mimsteel
Messages
7
Reaction score
0

Homework Statement



At one instant a bicyclist is 40.0m due east of a park's flagpole, going due south with a speed of 10.0m/s. Then 30.0s later, the cyuclist is 40.0m due north of the flagpole going due east with a speed of 10.0 m/s. For the cyclist in this 30.0s interval what are the A.) magnitude and B.) direction of the displacement, the C.) magnitude and direction of the average velocity and D.) the magnitude and direction of the average acceleration

Homework Equations



v=d/t
a=v2-v1/t

The Attempt at a Solution


not sure where to start really
 
Physics news on Phys.org
mimsteel said:

Homework Statement



At one instant a bicyclist is 40.0m due east of a park's flagpole, going due south with a speed of 10.0m/s. Then 30.0s later, the cyuclist is 40.0m due north of the flagpole...

I am confused here, how can a person due east who's going south end up in the north?
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
7K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
6
Views
2K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
8K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K