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## Main Question or Discussion Point

consider this IVP

y'=r-ky , y(0)=y0

y= (y0)e^(-kt) + (r/k)(1-e^(-kt))

if y,y0,r,t are provided, we should be able to solve for k and that's the problem but what I'm really interested is analyzing this problem

if we let y=0.99 (r/k) find t in terms of all other variables

Of courses, if y0 = 0 we can see that t= -(ln 0.01)/k

i wonder if y0 is not zero is it possible to analyze variable t using any knowledge or technology from mathematics?

this problems is derived from real application of pharmacokinetics IV infusion where

y= amount of drug at time t

y0 = initial amount of drug at t = 0

r = infusion rate

k = elimination rate constant

(r/k) = amount of drug at steady-state (as t --> infinity the amount of drug will approach this value and 99% of (r/k) is a good approximation of amount of drug at steady-state)

so what I really ask is how the initial amount of drug reflects the time to reach steady-state ( for example. how much we increase y0 in order to halve the time to reach steady-state )

y'=r-ky , y(0)=y0

y= (y0)e^(-kt) + (r/k)(1-e^(-kt))

if y,y0,r,t are provided, we should be able to solve for k and that's the problem but what I'm really interested is analyzing this problem

if we let y=0.99 (r/k) find t in terms of all other variables

Of courses, if y0 = 0 we can see that t= -(ln 0.01)/k

i wonder if y0 is not zero is it possible to analyze variable t using any knowledge or technology from mathematics?

this problems is derived from real application of pharmacokinetics IV infusion where

y= amount of drug at time t

y0 = initial amount of drug at t = 0

r = infusion rate

k = elimination rate constant

(r/k) = amount of drug at steady-state (as t --> infinity the amount of drug will approach this value and 99% of (r/k) is a good approximation of amount of drug at steady-state)

so what I really ask is how the initial amount of drug reflects the time to reach steady-state ( for example. how much we increase y0 in order to halve the time to reach steady-state )