Analyzing the Convergence of a McLauren Series

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SUMMARY

The discussion focuses on analyzing the convergence of a McLaurin series defined as (2x)^(n+1) / (n+1). The ratio test indicates that the interval of convergence is -1/2 < x < 1/2. At the endpoints, the series converges to 1/(n+1) at x=1/2 and (-1)^(n+1)/(n+1) at x=-1/2. The convergence of these series can be established using the limit comparison test and the alternating series test, respectively.

PREREQUISITES
  • Understanding of McLaurin series and their properties
  • Familiarity with the ratio test for convergence
  • Knowledge of the limit comparison test
  • Experience with the alternating series test
NEXT STEPS
  • Study the properties of McLaurin series in detail
  • Learn about the limit comparison test for series convergence
  • Explore the alternating series test and its applications
  • Investigate famous convergent and divergent series for comparison
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Students and educators in calculus, mathematicians analyzing series convergence, and anyone studying infinite series and their convergence properties.

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Homework Statement



Given a McLauren series: (2x)^n+1 / (n+1)

(a). Find interval of convergence.

Homework Equations



Limit test

The Attempt at a Solution



So I used ratio test and found that -1/2 <x<1/2. I am testing the end point. At x=1/2, the series will be 1/(n+1) and at x=-1/2, series is (-1)^n+1 / (n+1). How do I prove whether or not they are divergent or convergent. Does 1/ (n+1) converge to 0 ?

How about when x=-1/2, is it convergent or divergent ?
 
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I imagine you forgot to put the summation notation before your terms?? McLaurin series are infinite summations; anyways, 1/(n+1) converges to 0, but this is not sufficient to prove that it converges. Can you think of a fairly famous series that this reminds you of?? Similarly for the Alternating Series at x=(-1/2); although for the alternating series you could also use the alternating series test.
 
Do I compare 1/(n+1) to 1/n ??
 

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