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Introductory Physics Homework Help
Angle at which a ladder begins to slip
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[QUOTE="pech0706, post: 3219246, member: 305447"] [h2]Homework Statement [/h2] Consider the ladder in the figure. Assume there is friction between the verticle wall and the ladder, with the coeffecient of static friction=0.30. Find the angle at which the ladder just begins to slip. [h2]Homework Equations[/h2] [tex]\Sigma[/tex][tex]\tau[/tex]=0=N[SUB]w[/SUB]Lsin[tex]\Theta[/tex]-mg(L/2)sin(90-[tex]\Theta[/tex]) 0=+N[SUB]w[/SUB]Lsin[tex]\Theta[/tex]-mg(L/2)cos[tex]\Theta[/tex] [tex]\Sigma[/tex]F[SUB]x[/SUB][/=0=-N[SUB]w[/SUB]+F[SUB]friction[/SUB] [tex]\Sigma[/tex]F[SUB]y[/SUB]=0=N[SUB]F[/SUB]-mg F[SUB]friction[/SUB]=[tex]\mu[/tex][SUB]s[/SUB]N[SUB]F[/SUB]=[tex]\mu[/tex] [SUB]s[/SUB]mg tan[tex]\Theta[/tex]=1/2[tex]\mu[/tex][SUB]s[/SUB] [h2]The Attempt at a Solution[/h2] tan[tex]\Theta[/tex]=1/2(0.30) tan[SUP]-1[/SUP](1.667)=[tex]\Theta[/tex] 59=[tex]\Theta[/tex] I got 59 but the answer given by the book is 40 [/QUOTE]
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Angle at which a ladder begins to slip
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