Okay, so the problem is I need to find the radius of curvature for a proton moving through a uniform magnetic field with initial velocity v for some distance d and exiting at angle θ. I was able to get the correct answer; however, I think the apparent assumption made by the person making this problem is wrong.
sin θ = opposite/hypotenuse.
The Attempt at a Solution
This is what I think is wrong.
This is why I think it is wrong.
If my diagrams need to be further explicated, don't hesitate asking.
Last edited by a moderator: