Angular acceleration and force with constant angular velocity?

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SUMMARY

The discussion focuses on the dynamics of a mass moving in a circular path with constant angular velocity. Given a mass of 2 kg, a radius of 0.5 m, and a tension of 5 N in the string, the tangential speed is calculated to be √1.25 m/s, and the angular velocity is determined to be 0.5√1.25 m/s counterclockwise. The key conclusion is that while the angular velocity remains constant, the angular acceleration is zero, as there is no change in the rate of rotation. The centripetal acceleration is present due to the constant change in the direction of the linear velocity vector.

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cloudboy
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Homework Statement



A mass M=2kg moves at a constant speed constrained by a string to move in a circle with radius .5m on a frictionless table. The tension in the string is 5N.

What is the tangential speed?
What is the angular velocity?
What is the angular acceleration?
How much work has the rope done when the mass has gone through angle \pi?

Homework Equations



a_c = v^2/r
\omega=v_t/r

The Attempt at a Solution



I calculated that the tangential speed is equal to sqrt(1.25)m/s.
I also calculated that the angular velocity is (.5)(sqrt(1.25) m/s counterclockwise from the positive x-axis.

But how do I do the angular acceleration?

Is the force equal to zero, because the force is to the center and the direction is tangential?
 
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cloudboy said:
But how do I do the angular acceleration?

Is the force equal to zero, because the force is to the center and the direction is tangential?

Is the mass speeding up or slowing down, or does it have a constant speed?
 
Constant speed
 
cloudboy said:
Constant speed

So if the speed is constant, what does that say about the angular acceleration? Is the rotation rate changing?
 
ω is constant, but it is uniformly changing direction. So there has to be an angular acceleration.

edit --

but since angular acceleration = tangential accel. / r -- would angular acceleration = 0?
 
cloudboy said:
ω is constant, but it is uniformly changing direction. So there has to be an angular acceleration.

ω is not changing direction. It's a vector that's perpendicular to the plane of motion, i.e., it lies along the rotational axis. Angular acceleration, \alpha is the rate of change of ω, and if ω is constant, \alpha is zero.

On the other hand, since the linear velocity vector is changing with time, there IS linear acceleration. This acceleration is in fact the centripetal acceleration (always pointing towards the center of motion).
 
Ok thanks a lot! I really appreciate the help. I just didn't have a firm grasp on the concept.
 

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