Angular acceleration of a drill

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Homework Help Overview

The problem involves a dentist's drill that starts from rest and experiences a constant angular acceleration, reaching a final angular velocity of 24400 revolutions per minute after 3.07 seconds. The goal is to determine the angular acceleration in rad/s².

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conversion of angular velocity from revolutions per minute to radians per second and its relevance to the problem. There are inquiries about the relationship between angular velocity and angular acceleration, as well as the application of kinematic equations in rotational motion.

Discussion Status

Some participants have offered guidance on using angular kinematic equations and conversions between units. There is an exploration of how to calculate the angle of rotation and the implications of initial conditions on the equations used. Multiple interpretations of the problem and its components are being examined.

Contextual Notes

Participants note the importance of understanding the units involved and the assumptions related to angular motion. There is a discussion about the validity of using linear kinematic equations in the context of rotational motion.

notsam
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Homework Statement

A dentist’s drill starts from rest. After 3.07 s
of constant angular acceleration, it turns at a
rate of 24400 rev/min.
Find the drill’s angular acceleration.
Answer in units of rad/s2.



Homework Equations

F=mv^2/r, vi=vf+at, a=v^2/r



The Attempt at a Solution

The part that I don't understand is how 2440 rev/min is related to the other units. If I knew this I could probably solve it.
 
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how many radians will be covered one revolution ?

just put that and use 60s for 1min .. you'get speed in rad/s
 
And rads/sec can be used as a velocity?
 
rad/s is angular velocity... 2(pi) rad = 1 rev i believe
 
use eqn of on velocity not linear velocity to solve this question

w = wo + αt
 
Thanks! This isn't part of the homework but I am curious because my teacher said that it would be on the test, what if I wanted to find the angle that the drill rotates? Since I have 24400 rev/min = 2555 rad/sec over an interval of 3.07 s, I would multiply 2555 x 3.07 which would give me radians and then convert it to degrees?
 
all the Newton eqn's are valid for rotation in angular form

2555 x 3.07 will not work as you have acceleration

Try this:

θ = wot + 0.5αt2

Which come from

s = ut + 0.5at2
 
*just use:

s = θr
v = wr
a = αr


for all Newton eqn to convert them to rotation one ! :)
 
No way? So when it's at rest it simplifys to s=.5at^2? And s= arc legth in radians?
 
  • #10
notsam said:
No way? So when it's at rest "initially" it simplifys to s=.5at^2? And s= arc legth in radians?
length cannot be in radian ... rad is a pure number .. length is in meters
 
  • #11
Ok so the basic kinematic equation for distance can also be used for angles when using angular acceleration. That is SO helpful that just opened up a door in my mind I understand this matertial so much more now!
 
  • #12
Yes they can be
i already gave you 2

last one is : w2 = wo2 + 2αθ
 
  • #13
2555 rads/sec is the final velocity after 3.07 seconds of constant acceleration.
 

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